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3 years ago

11

The process during which cells of the body harness energy from food consumed by a living organism is ______________________.

1 answer:

o-na [289]3 years ago

5 0

It is called Cellular Respiration

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The hydrogen-line emission spectrum includes a line at a wavelength of 434 nm. What is the energy of this radiation? (h= 6.626 x

Andrews [41]

Wavelength = 434nm = 434 x 10⁻⁹m
planck's constant = <span>h= 6.626 x 10 ⁻³⁴ J
E =?
by using the formula;
E = hc /</span>λ
value for c is 3 x 10⁸ m/s
E = (6.626 x 10 ⁻³⁴ J)(3 x 10⁸ m/s) / 434 x 10⁻⁹m
E = 1.9878 x 10⁻²⁵ / 434 x 10⁻⁹m
E = 4.58 x 10⁻¹⁹ joules

6 0

3 years ago

Do you think it matters if you

vovikov84 [41]

Answer:

yes I do think they mean the same thing

Explanation:

150 grams and 150 grams is the same thing and adding 0 to the end of a decimal does not change its value, you could even put 150.0000000 grams and it would still be equivalent to the other numbers

5 0

3 years ago

An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average

Deffense [45]

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = $\frac{Displacement }{Change in time}$ = Δx / Δt = $\frac{x2 - x1}{t2 - t1}$

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{2100km }{1000km/h}$

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{1300km }{800km/h}$

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = $\frac{x2 - x1}{t2 - t1}$

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = $\frac{1300 - 2100}{1.625 - 2.1}$

Average velocity = 1684.21 km/h

7 0

3 years ago

What group is helium in? Group 8 or group 2?

Gemiola [76]

Answer:

group 8 of the periodic table

Explanation:

7 0

3 years ago

Read 2 more answers

The most important commercial ore of chromium is chromite (FeCr2O4). One of the steps in the process used to extract chromium fr

Mars2501 [29]

Answer:

1 mole FeCr2/ 1 mole FeCr2O4

Explanation:

We have to write down the equation of the reaction before we can answer the question;

2C(s) + FeCr2O4(s) -------> FeCr2(s) + 2CO2(g)

By inspection of this reaction equation, we can clearly see that the mole ratio of the reactants and products is 2:1:1:2.

Specifically, the ratio of chromites to ferrochrome is 1:1

Hence;

The mole ration required to convert chromites to ferrochrome is;

1 mole FeCr2/ 1 mole FeCr2O4

4 0

3 years ago