What are the steps to a graph a quadratic function
1 answer:
You need 3 points to graph a quadratic function.
It is advisable that one of these points be the vertex, because the line of symmetry passes through it
Next, you need to find two other points that lie on the curve, replacing an x-value into the function and calculating the y-value. It is easier if these two points are at the same distance from the line of symmetry.
For example, if the quadratic function is y = (x - 4)² + 3, the vertex is located at (4, 3). Replacing with x = 3 into the equation, we get:
y = (3 - 4)² + 3
y = 1 + 3
y = 4
Replacing with x = 5 into the equation, we get:
y = (5 - 4)² + 3
y = 1 + 3
y = 4
Now, we need to connect the points (3, 4), (4, 3), and (5, 4) with a U shape, as follows:
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Answer:
With garlic treatment, the mean change in LDL cholesterol is not greater than 0.
Step-by-step explanation:
The dependent <em>t</em>-test (also known as the paired <em>t</em>-test or paired samples <em>t</em>-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.
In this case a paired <em>t</em>-test is used to determine the effectiveness of garlic for lowering cholesterol.
A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.
The hypothesis for the test can be defined as follows:
<em>H₀</em>: With garlic treatment, the mean change in LDL cholesterol is not greater than 0, i.e. <em>d</em> ≤ 0.
<em>Hₐ</em>: With garlic treatment, the mean change in LDL cholesterol is greater than 0, i.e. <em>d</em> > 0.
The information provided is:
Compute the test statistic value as follows:
The test statistic value is 0.22.
Decision rule:
If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Compute the <em>p</em>-value of the test as follows:
*Use a <em>t</em>-table.
The <em>p</em>-value of the test is 0.4132.
<em>p-</em>value= 0.4132 > <em>α</em> = 0.01
The null hypothesis was failed to be rejected.
Thus, it can be concluded that with garlic treatment, the mean change in LDL cholesterol is not greater than 0.