The number of bacteria in a culture grows at a rate that is proportional to the number present. initially, there were 10 bacteri
a in the culture. if the doubling time is equal to 3 hours, what is the number of bacteria present after 24 hours?
1 answer:
N = 10(2)^t where N = number of bacteria and t = time in multiples of 3 hours
So when t = 24/3 we have
N = 10 (2)^8 = 2560 answer
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X-5= 20
x-5= -20
Absolute value makes a negative positive, so when you are solving x-5 could have been 20 originally or -20 originally. Solve for both.
F(9)
sub 9 forx
f(9)=5(9)-16
f(9)=45-16
f(9)=29
f(9)=29
Comment if you want me to give you the step by step thank you
Answer:
nucleic acid
Step-by-step explanation:
