3 years ago

Please include work

Mathematics

1 answer:

OLga [1]3 years ago

7 0

Answer:

9. 6k + 5 and 2k - 1.

10. 5√2 .

Step-by-step explanation:

9. Area = 12k^2 + 4k - 5

Factoring:

12k^2 - 6k + 10k - 5

= 6k(2k - 1) + 5(2k - 1)

= (6k + 5)(2k - 1)

So the required lengths are 6k + 5 and 2k - 1.

10. The ratio of a leg to the hypotenuse is 1: √2 so if the hypotenus = 10 the length of a leg is 10 / √2

= 10 √2 / 2

= 5√2 .

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