Question

Please include work

Answer 1

Answer:

9.     6k + 5 and 2k - 1.

10.    5√2 .

Step-by-step explanation:

9.    Area = 12k^2 + 4k - 5

Factoring:

12k^2 - 6k + 10k - 5

= 6k(2k - 1) + 5(2k - 1)

= (6k + 5)(2k - 1)

So the required lengths are 6k + 5 and 2k - 1.

10.  The ratio of a leg to the hypotenuse is  1: √2 so if the hypotenus = 10 the length of a leg is 10 / √2  

= 10 √2  / 2

= 5√2 .