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kobusy [5.1K]
2 years ago
15

Finding the length of arc and and sector area? Genuinely confused and will mark for brainliest.

Mathematics
2 answers:
SOVA2 [1]2 years ago
7 0

Answer:

Arc length = =\frac{5}{4} \pi \,km=1.25\ \pi\,\,km

Area=\frac{25}{8}\,  \pi\,\,km^2= 3.125\, \pi\,\,km^2

Step-by-step explanation:

For the length of an arc of circumference, you need to recall the formula:

arc = R * \theta

which is the product of the radius R times the angle, but only valid if the angle \theta is given in radians (not degrees). So we need to change the 45 degree angle into radians. we can do so by remembering that \pi radians is the same as 180°, and then the following proportion can be written to find what is the value (x) of 45° in radians:

\frac{45^o}{180^o} = \frac{x}\pi} \\x=\frac{45^o}{180^o} \,\pi\\x=\frac{\pi}{4}

Now we find the length of the arc using the formula given above:

arc = R * \theta\\arc=5\,km\,\frac{\pi}{4} \\arc=\frac{5}{4} \pi \,km

Now for the area of the sector, recall the formula:

Area = \frac{1}{2} R^2\,\theta

with the same condition for \theta of being expressed in radians (and not degrees). So the formula becomes:

Area = \frac{1}{2} R^2\,\theta\\Area= \frac{1}{2} (5\,km)^2\,\frac{\pi}{4} \\Area=\frac{25}{8}\,  \pi\,\,km^2

LiRa [457]2 years ago
5 0

Answer:

5 &x = 14

Step-by-step explanation:

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Which statements are true about David's work? Check all that apply. The GCF of the coefficients is correct. The GCF of the varia
Anon25 [30]

Answer:

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

In step 6, David applied the distributive property.

Step-by-step explanation:

Given the polynomial :

80b⁴ – 32b²c³ + 48b⁴c

The Greatest Common Factor (GCF) of the coefficients:

80, 32, 48

Factors of :

80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80

32 : 1, 2, 4, 8, 16, and 32

48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.

GCF = 16

b⁴, b², b⁴

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b² = b * b

b⁴ = b * b * b * b

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From the polynomial ; 80b⁴ does not contain c ; so factoring out c is incorrect

In step 6 ; the distributive property was used to obtain ; 16b²c(5b² – 2c² + 3b²)

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