2 years ago

NEED Help again peace and love kombayah

Mathematics

1 answer:

Arlecino [84]2 years ago

8 0

25•15=365-50=315 so that is the answer

You might be interested in

Every point on the perpendicular bisector of a segment is?

lisov135 [29]

Its equally distant from the endpoints of the segment to find the center of the following rotation

8 0

3 years ago

Read 2 more answers

At the school cafeteria, each student who ordered lunch gets 6 chicken nuggets. The cafeteria staff prepares enough for 300 kids

lesya [120]

1800.... 300 students x 6 nuggets per student= 1800 total :)

4 0

2 years ago

Can someone answer these please? I just don’t understand

Ber [7]

can you get a better picture of it so I can possibly find the answer.

8 0

2 years ago

Simplify the expression:<br> (3n)(2)

Arlecino [84]

Answer:

Step-by-step explanation:

3n+2)! / (3n-3)! = (3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)*(3n-3)! divided by (3n-3)! which becomes:

23! / 18! = (23 * 22 * 21 * 20 * 19 * 18! divided by 18! which becomes:

(23 * 22 * 21 * 20 * 19)

the result is 4037880

i used my ti-84 to take 23! and divide it by 18! and i got 4037880.

this confirms the solution is correct.

8 0

2 years ago

Read 2 more answers

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

3 0

2 years ago