Answer:
Step-by-step explanation:
We choose arbitrary values for x and in each case calculate y = 2x + 5.
If x = 0, y = 5; if x = 3, y = 11, and so on.
How? when x = 3, y = 2(3) + 5 = 6 + 5 = 11.
The table, with rows and columns suitable to this problem, would look like:
x y
0 5
3 11
10 25
and so on
Answer:
Step-by-step explanation: The answer is 6 friends. Assuming that the group is going in one car. Leaving them with 100.5 to spend on admission.You can add the admission fee 6 times until they have nothing left
5 odd numbers and 5 even numbers
since they can be repeated
5*5*5=first 3 digits
5*5*5=last 3 digits
in all
5*5*5*5*5*5=15625 ways
I Domitila get hungry :
Step-by-step explanation:
