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Maurinko [17]
2 years ago
6

Question 1(Multiple Choice Worth 1 points)

Mathematics
2 answers:
Romashka [77]2 years ago
7 0

Answer:

5%

Step-by-step explanation:

Lets say 10 add a 0 = 100 9.5 add a 0 = 95.0 (move ok decimal place) so there is a 5% error.

olga55 [171]2 years ago
7 0

Answer:

Step-by-step explanation:

no

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ira [324]
∑x = 5 + 7 + 8 + 4 + 11 + 12 + 8 + 7 = 62
(∑x)^2 = 62^2 = 3,844
x bar = 62 / 8 = 7.75
∑x^2 = 25 + 49 + 64 + 16 + 121 + 144 + 64 + 49 = 522

∑y = 79 + 82 + 83 + 81+ 86 + 89 + 91 + 84 = 675
(∑y)^2 = 455,625
y bar = 675 / 8 = 84.375
∑y^2 = 6,241 + 6,724 + 6,889 + 6,561 + 7,396 + 7,921 + 8,281 + 7,056 = 57,069

∑xy = 395 + 574 + 664 + 324 + 946 + 1,068 + 728 + 588 = 5,287
 
r = (∑xy - n(x bar)(y bar)) / (sqrt(∑x^2 - n(x bar)^2) sqrt(∑y^2 - n(y bar)^2)) = (5,287 - 8(7.75)(84.375)) / (sqrt(522 - 8(7.75)^2) sqrt(57,069 - 8(84.375)^2)) = (5,287 - 5,231.25) / (sqrt(522 - 480.5) sqrt(57,069 - 56,953.125)) = 55.75 / (sqrt(41.5) sqrt(115.875)) = 55.75 / 69.3456 = 0.8039




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3 years ago
Which of the binomials below is a factor of this trinominal? x^2-13+30
Leona [35]

Answer:

(x-3)(x-10)

Step-by-step explanation:

To factor the equation, break it into two binomials which multiply to make the equation. To write these binomials (x+a)(x+b), find factors which multiply to 30 and add to -13 for a and b.

30: 1, 2, 3, 5, 6, 10, 15, 30

-3+-10 = -13

x^2-13x+30 = (x-3)(x-10)

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Step-by-step explanation:

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3 years ago
Calculus graph please help
tresset_1 [31]

Answer:

See Below.

Step-by-step explanation:

We are given the graph of <em>y</em> = f'(x) and we want to determine the characteristics of f(x).

Part A)

<em>f</em> is increasing whenever <em>f'</em> is positive and decreasing whenever <em>f'</em> is negative.

Hence, <em>f</em> is increasing for the interval:

(-\infty, -2) \cup (-1, 1)\cup (3, \infty)

And <em>f</em> is decreasing for the interval:

\displaystyle (-2, -1) \cup (1, 3)

Part B)

<em>f</em> has a relative maximum at <em>x</em> = <em>c</em> if <em>f'</em> turns from positive to negative at <em>c</em> and a relative minimum if <em>f'</em> turns from negative to positive to negative at <em>c</em>.

<em>f'</em> turns from positive to negative at <em>x</em> = -2 and <em>x</em> = 1.

And <em>f'</em> turns from negative to positive at <em>x</em> = -1 and <em>x</em> = 3.

Hence, <em>f</em> has relative maximums at <em>x</em> = -2 and <em>x</em> = 1, and relative minimums at <em>x</em> = -1 and <em>x</em> = 3.

Part C)

<em>f</em> is concave up whenever <em>f''</em> is positive and concave down whenever <em>f''</em> is negative.

In other words, <em>f</em> is concave up whenever <em>f'</em> is increasing and concave down whenever <em>f'</em> is decreasing.

Hence, <em>f</em> is concave up for the interval (rounded to the nearest tenths):

\displaystyle (-1.5 , 0) \cup (2.2, \infty)

And concave down for the interval:

\displaystyle (-\infty, -1.5) \cup (0, 2.2)

Part D)

Points of inflections are where the concavity changes: that is, <em>f''</em> changes from either positive to negative or negative to positive.

In other words, <em>f </em>has an inflection point wherever <em>f'</em> has an extremum point.

<em>f'</em> has extrema at (approximately) <em>x</em> = -1.5, 0, and 2.2.

Hence, <em>f</em> has inflection points at <em>x</em> = -1.5, 0, and 2.2.

7 0
2 years ago
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