All categories

3 years ago

What is the measure of the missing angle?

Mathematics

1 answer:

nikitadnepr [17]3 years ago

8 0

Answer:

30.96°

Step-by-step explanation:

Use tan(x) = opposite/adjacent

tan(x) = 12/20

tan(x) = 0.6

x = (tan^-1)(0.6)

x = 30.964

You might be interested in

In a baseball card collection, 40% of the cards are worth more than 100$. If 12 cards in the collection are worth more than $100

Helen [10]

Answer:

Step-by-step explanation:

12 is 40% of the total number of cards.

12 = 0.4x, where x is total number of cards

/0.4 /0.4

30 = x

30 cards

5 0

3 years ago

Read 2 more answers

Inveres laplace transform (3s-14)/s^2-4s+8

Olenka [21]

Complete the square in the denominator.

$s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4$

Rewrite the given transform as

$\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}$

Now take the inverse transform:

$L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}$

5 0

3 years ago

Which shape is both rectangle and a square?

mina [271]

Step-by-step explanation:

the rhombus is both rectangle and square

8 0

3 years ago

Read 2 more answers

Number two please <br> ASAP

miv72 [106K]

The solutions for $-5 +2x^{2} = -6x$ is option 3. $x= \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .$

Step-by-step explanation:

Step 1:

First, we must bring the equation to the form of $ax^{2} +bx +c =0.$

So $-5 +2x^{2} = -6x$ becomes $2x^{2} +6x-5=0.$

The value of a is the coefficient of the $x^{2}$ term, the value of b is the coefficient of x term and c is the coefficient of the constant term.

Comparing the above equation to $ax^{2} +bx +c =0,$ we get $a = 2, b = 6,$ and $c=-5.$

We have the formula $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.$

Step 2:

By substituting the known values, we get

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} =\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)}.$

$\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)} = \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .$

This is the third option.

8 0

4 years ago

does the ordered pair (-2, 1.5) fall inside both the trapezoid and the circle? Explain why or why not?

Rina8888 [55]

It only falls inside the trapezoid bc the circle goes through the point (0,2) so it isnt on 1.5

7 0

4 years ago