Suppose you have a coffee mug with a circular cross section and vertical sides (uniform radius). What is its inside radius if it
holds 400.0 g of coffee when filled to a depth of 6.00 cm? Assume coffee has the same density of water. Answer in cm.
1 answer:
Coffee mug is cylindrical shape. Therefore,
Volume of mug = volume of cylinder = πr²h
r = inner radius of mug. h = height of coffee = 6 cm.
Density of coffee = Density of water = 1 g/ml
Therefore, volume of coffee = mass/density = 400/1 = 400 ml = 400 cm³
Volume of coffee = πr²h
400= πr²(6)
r² = 21.23
r = inner radius of mug = 4.607 cm
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