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MatroZZZ [7]
3 years ago
5

HELP PLEASE!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (20pts)

Physics
2 answers:
anyanavicka [17]3 years ago
8 0

Explanation:

potential energy =360800J

mass(m)=?

height (h)=25m

g=9.8m/s²

we have

potential energy =360800J

mgh=360800J

m×9.8×25=360800

m=360800/(9.8×25)=1472.653061kg

Archy [21]3 years ago
8 0

Answer:

HELP PLEASE!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted!

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How are the surface of Mercury and Mars similar to the surface of the Earth?
scZoUnD [109]

Answer:

The terrestrial planets all have rocky surfaces that feature mountains, plains, valleys and other formations. ... Mars has very low atmospheric pressure, and Mercury has almost none, so craters are more common on these planets.

Explanation:

8 0
2 years ago
HELP WILL GIVE BRAINLIEST IF CORRECT
anastassius [24]
It’s B i literally jus learned this
6 0
3 years ago
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An electron travels 1.92 m in 4.47 × 10−8 s. How fast is it traveling?<br> Answer in units of m/s.
malfutka [58]
Speed = (distance covered) / (time to cover the distance).

             =  (1.92 meters)  /  (4.47 x 10⁻⁸ second)

            = 42,950,000 meters/second  (rounded to the nearest 10,000 m/s)

That's about  96.1 million miles per hour, or about 14% of the speed of light.


6 0
3 years ago
The index of refraction of a transparent substance is 1.7, and the speed of light in air is 3.00 · 108 s. Calculate the speed of
Natalija [7]
Given the index of refraction, n and speed of light in the vacuum, c, we can solve for the speed of light in the transparent substance by the equation below.
                                                n = c / v
where v is our unknown.
Substituting the known values,
                                            1.7 = (3 x 10^8 m/s) / v
The value of v is equal to 1.76 x 10^8 m/s. 
5 0
3 years ago
An electron of mass 9.11×10-31kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to t
SOVA2 [1]

Answer:

(A) Acceleration will be 240.3846\times 10^{12}m/sec^2

(b) Time taken will be 1.4\times 10^{-8}sec

(c) Force will be 2189.9\times 10^{-19}N              

Explanation:

We have given that electron starts from rest so initial velocity u = 0 m/sec

Final velocity v=2.50\times 10^6m/sec

Mass of electron m=9.11\times 10^{-31}kg

Distance traveled by electron s=1.30cm =0.013m

From third equation of motion we know that v^2=u^2+2as

(a) So (2.5\times 10^6)^2=0^2+2\times a\times 0.013

a=240.3846\times 10^{12}m/sec^2

(b) From first equation of motion we know that v = u+at

So 2.50\times 10^6=0+240.3846\times 10^{12}t

t=0.014\times 10^{-6}=1.4\times 10^{-8}sec

(c) From newton's law we know that force

F=ma=9.11\times 10^{-31}\times 240.3846\times 10^{12}=2189.9\times 10^{-19}N

7 0
3 years ago
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