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Lisa [10]
2 years ago
10

A straight, cylindrical wire lying along the x axis has a length L and a diameter d . It is made of a material described by Ohm'

s law with a resistivity rho . Assume potential V is maintained at the left end of the wire at x = 0. Also assume the potential is zero at x=L . In terms of L, d , V, rho, and physical constants, derive expressions for (a) the magnitude and direction of the electric field in the wire,
Physics
1 answer:
Zepler [3.9K]2 years ago
7 0

The magnitude and direction of the electric field in the wire are mathematically given as

L &=[(v / L) v / m] \hat{i}

<h3>What is the magnitude and direction of the electric field in the wire?</h3>

Generally, the equation for is  mathematically given as

A cylindrical wire that is straight and parallel to the x-axis has the following dimensions: length L, diameter d, resistivity p, diameter d, potential v, and z length. combining elements from both sides  

E d x=\int d v.

\begin{aligned}&-E \int_0^L d x=\int_v^0 d v \\\therefore E \cdot L &=v \\L &=[(v / L) v / m] \hat{i}\end{aligned}

In conclusion, the magnitude and direction of the electric field in the wire are given as

L &=[(v / L) v / m]

Read more about electric fields

brainly.com/question/15800304

#SPJ4

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To solve this problem it is necessary to apply the concepts related to transformers, that is to say passive electrical device that transfers electrical energy from one electrical circuit to one or more circuits.

From the mathematical definition we have that the relationship between the voltage of the first coil and the second coil is proportional to the number of loops of the first and second loop, that is:

\frac{V_s}{V_p} = \frac{N_s}{N_p}

Where

V_p =  input voltage on the primary coil.

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Replacing our values we have:

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Replacing,

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From the same relations of number of turns and the voltage of the first and second coil we also have the relation of electricity and voltage whereby:

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