A straight, cylindrical wire lying along the x axis has a length L and a diameter d . It is made of a material described by Ohm'

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A straight, cylindrical wire lying along the x axis has a length L and a diameter d . It is made of a material described by Ohm'

s law with a resistivity rho . Assume potential V is maintained at the left end of the wire at x = 0. Also assume the potential is zero at x=L . In terms of L, d , V, rho, and physical constants, derive expressions for (a) the magnitude and direction of the electric field in the wire,

Physics

1 answer:

Zepler [3.9K] · Answer 1 · 2023-08-03T01:01:49+03:00

The magnitude and direction of the electric field in the wire are mathematically given as

$L &=[(v / L) v / m] \hat{i}$

<h3>What is the magnitude and direction of the electric field in the wire?</h3>

Generally, the equation for is mathematically given as

A cylindrical wire that is straight and parallel to the x-axis has the following dimensions: length L, diameter d, resistivity p, diameter d, potential v, and z length. combining elements from both sides

E d $x=\int d v.$

$\begin{aligned}&-E \int_0^L d x=\int_v^0 d v \\\therefore E \cdot L &=v \\L &=[(v / L) v / m] \hat{i}\end{aligned}$

In conclusion, the magnitude and direction of the electric field in the wire are given as

$L &=[(v / L) v / m]$