Answer:
![T=2.5*10^{-3}s](https://tex.z-dn.net/?f=T%3D2.5%2A10%5E%7B-3%7Ds)
Explanation:
From the question we are told that:
Beat frequency ![F_b=4](https://tex.z-dn.net/?f=F_b%3D4)
Frequency ![F=400Hz](https://tex.z-dn.net/?f=F%3D400Hz)
Generally the equation for Frequency of the violin is mathematically given by
![f_v=F_b+F](https://tex.z-dn.net/?f=f_v%3DF_b%2BF)
![f_v=4+400Hz](https://tex.z-dn.net/?f=f_v%3D4%2B400Hz)
![f_v=404Hz](https://tex.z-dn.net/?f=f_v%3D404Hz)
Therefore the period of the violin string oscillations is
![T=\frac{1}{f_v}](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B1%7D%7Bf_v%7D)
![T=\frac{1}{404}](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B1%7D%7B404%7D)
![T=2.5*10^{-3}s](https://tex.z-dn.net/?f=T%3D2.5%2A10%5E%7B-3%7Ds)
C. change length and direction
Explanation:
The density of the material in which the light wave is travelling affects the speed of the wave. Different materials have different densities and they effect differently light waves which travel through them. Light waves may change direction at the boundary between two transparent materials, depending on material density. Density also impacts the speed of light. The denser the material, the slower light travels through it. The wavelength also decreases as light travels through the denser medium.
Answer:
23. 4375 m
Explanation:
There are two parts of the rocket's motion
1 ) accelerating (assume it goes upto h1 height )
using motion equations upwards
![s = ut+\frac{1}{2}*a*t^{2} \\h_1=0+\frac{1}{2}*5*2.5^{2} \\=15.625 m](https://tex.z-dn.net/?f=s%20%3D%20ut%2B%5Cfrac%7B1%7D%7B2%7D%2Aa%2At%5E%7B2%7D%20%5C%5Ch_1%3D0%2B%5Cfrac%7B1%7D%7B2%7D%2A5%2A2.5%5E%7B2%7D%20%5C%5C%3D15.625%20m)
Lets find the velocity after 2.5 seconds (V1)
V = U +at
V1 = 0 +5*2.5 = 12.5 m/s
2) motion under gravity (assume it goes upto h2 height )
now there no acceleration from the rocket. it is now subjected to the gravity
using motion equations upwards (assuming g= 10m/s² downwards)
V²= U² +2as
0 = 12.5²+2*(-10)*h2
h2 = 7.8125 m
maximum height = h1 + h2
= 15.625 + 7.8125
= 23. 4375 m
Answer : Relatively hot objects
Explanation : We know that, the temperature of the objects is inversely proportional to their wavelengths. The objects emitting radiation in the visible region have short wavelength and hence are relatively hotter.
We know the range of wavelength of the visible spectrum is from 400 nm to 780 nm.