1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lisa [10]
2 years ago
10

A straight, cylindrical wire lying along the x axis has a length L and a diameter d . It is made of a material described by Ohm'

s law with a resistivity rho . Assume potential V is maintained at the left end of the wire at x = 0. Also assume the potential is zero at x=L . In terms of L, d , V, rho, and physical constants, derive expressions for (a) the magnitude and direction of the electric field in the wire,
Physics
1 answer:
Zepler [3.9K]2 years ago
7 0

The magnitude and direction of the electric field in the wire are mathematically given as

L &=[(v / L) v / m] \hat{i}

<h3>What is the magnitude and direction of the electric field in the wire?</h3>

Generally, the equation for is  mathematically given as

A cylindrical wire that is straight and parallel to the x-axis has the following dimensions: length L, diameter d, resistivity p, diameter d, potential v, and z length. combining elements from both sides  

E d x=\int d v.

\begin{aligned}&-E \int_0^L d x=\int_v^0 d v \\\therefore E \cdot L &=v \\L &=[(v / L) v / m] \hat{i}\end{aligned}

In conclusion, the magnitude and direction of the electric field in the wire are given as

L &=[(v / L) v / m]

Read more about electric fields

brainly.com/question/15800304

#SPJ4

You might be interested in
What is Newton’s second law of motion
ddd [48]

"<em>F = dP/dt. </em> The net force acting on an object is equal to the rate at which its momentum changes."

These days, we break up "the rate at which momentum changes" into its units, and then re-combine them in a slightly different way.  So the way WE express and use the 2nd law of motion is

"<em>F = m·A.</em>  The net force on an object is equal to the product of the object's mass and its acceleration."

The two statements say exactly the same thing. You can take either one and work out the other one from it, just by working with the units.

8 0
3 years ago
Read 2 more answers
A projectile is launched diagonally into the air and has a hang time of 24.5 seconds. Approximately how much time is required fo
Rasek [7]

Answer:

t=12.25\ seconds

Explanation:

<u>Diagonal Launch </u>

It's referred to as a situation where an object is thrown in free air forming an angle with the horizontal. The object then describes a known path called a parabola, where there are x and y components of the speed, displacement, and acceleration.

The object will eventually reach its maximum height (apex) and then it will return to the height from which it was launched. The equation for the height at any time t is

x=v_ocos\theta t

\displaystyle y=y_o+v_osin\theta \ t-\frac{gt^2}{2}

Where vo is the magnitude of the initial velocity, \theta is the angle, t is the time and g is the acceleration of gravity

The maximum height the object can reach can be computed as

\displaystyle t=\frac{v_osin\theta}{g}

There are two times where the value of y is y_o when t=0 (at launching time) and when it goes back to the same level. We need to find that time t by making y=y_o

\displaystyle y_o=y_o+v_osin\theta\ t-\frac{gt^2}{2}

Removing y_o and dividing by t (t different of zero)

\displaystyle 0=v_osin\theta-\frac{gt}{2}

Then we find the total flight as

\displaystyle t=\frac{2v_osin\theta}{g}

We can easily note the total time (hang time) is twice the maximum (apex) time, so the required time is

\boxed{t=24.5/2=12.25\ seconds}

4 0
3 years ago
A van has a weight of 4000 lb and center of gravity at Gv. It carries a fixed 900 lb load which has a center of gravity at Gl. I
natulia [17]

Answer:

 x = 25 / μ     [ ft]

Explanation:

To solve this exercise we can use Newton's second law.

Let's set a reference system where the x axis is parallel to the road

Y axis  

       N_B + N_A - W_van - W_load = 0

       N_B + N_A = W_van + W_load

X axis

     fr = ma

     a = fr / m

the total mass is

        m = (W_van + W_load) / g

the friction force has the expression

      fr = μ N_{total}

      fr = μy (W_van + W_load)

we substitute

      a = μ (W_van + W_load)    \frac{g}{W_van + W_load}

      a = μ g

taking the acceleration let's use the kinematic relations where the final velocity is zero

       v² = v₀² - 2 a x

       0 = v₀² -2a x

        x = \frac{v_o^2}{2a}

        x = \frac{v_o^2}{2 \mu g}

        x = \frac{40^2}{2 \ 32 \  \mu}

        x = 25 / μ     [ ft]

5 0
3 years ago
2. Michelle bought 15.6 yards of fabric. She used 5.43 yards in her art 10 points
viktelen [127]
Do find the percentage you:
5.43/15.6=0.34

Time by 100:
34%

Closest answer is 35%

Hope this helps ;)
8 0
3 years ago
What is 8 m/s - 3 m/s?
Dima020 [189]

5m/s 8-3 is five so five


3 0
3 years ago
Other questions:
  • Can someone help me with this whole page? i can't seem to figure it out. Is physics homework
    6·1 answer
  • Can a person be moving in a positive direction even if their acceleration vector is negative ?
    15·2 answers
  • Elements in an blank or blank of the periodic table have similar characteristics
    15·1 answer
  • Swinging a golf club or baseball bat are examples of ______________ stretching.
    15·1 answer
  • An object with a mass of 21 kilograms is lifted through a distance of 7 meters how much work is done
    15·1 answer
  • 4. How does the type of medium affect a sound wave?
    10·1 answer
  • Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker poi
    6·1 answer
  • A 200 turn coil is in a uniform magnetic field that is decreasing at the rate 0.20 T/s. The coil is perpendicular to the field a
    14·1 answer
  • Select all of the answers that apply.
    15·2 answers
  • Su una strada rettilinea ci sono due semafori che distano 98 m e che diventano verdi contemporaneamente. Dal primo semaforo part
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!