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tresset_1 [31]
3 years ago
14

We calculated the speed of visible light through four substances. What is different about the substances? Lesson: 4.10 Substance

Speed of Sound A 350 m/s B 1000 m/s C С 1500 m/s D 5000 m/s Their weights are different Their shapes are different Their pressures are different Their densities are different​
Physics
1 answer:
marusya05 [52]3 years ago
3 0

Answer:

it's to dense

Explanation:

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Which type of electromagnetic waves has the shortest wavelength?<br> The answer is Ultraviolet
jarptica [38.1K]

Answer:

Gamma Rays .

Explanation:

3 0
3 years ago
Read 2 more answers
. Calcula el módulo del vector resultante de dos vectores fuerza de 9 [N] y 12 [N] concurrentes en un punto o, cuyas direcciones
ycow [4]

Answer:

a) 20.29N

b) 19.42N

c) 15N

Explanation:

To find the magnitude of the resultant vector you can consider an axis in the middle of the vector, from which you can calculate the components of the vectors by using the angles given:

a) for 30°

F_1=[9cos(15\°)\hat{i}+9sin(15\°)\hat{j}]N\\\\F_1=[8.69\hat{i}+2.32\hat{j}]N\\\\F_2=[12cos(15\°)\hat{i}-12sin(15\°)\hat{j}]N\\\\F_2=[11.59\hat{i}-3.10\hat{j}]N\\\\F=F_1+F_2=20.28N\hat{i}-0.78N\hat{j}\\\\|F|=\sqrt{(20.28N)^2+(0.78N)^2}=20.29N

F = 20.29N

b)  for 45°

F_1=[9cos(22.5\°)\hat{i}+9sin(22.5\°)\hat{j}]N\\\\F_1=[8.31\hat{i}+3.44\hat{j}]N\\\\F_2=[12cos(22.5\°)\hat{i}-12sin(22.5\°)\hat{j}]N\\\\F_2=[11.08\hat{i}-4.59\hat{j}]N\\\\F=F_1+F_2=19.39N\hat{i}-1.15\hat{j}\\\\|F|=\sqrt{(19.39N)^2+(1.15N)^2}=19.42N

F= 19.42N

c) for 90°

for this case you can consider that the direction of both vectors are the y and x axis of the Cartesian plane:

F_1=9N\hat{i}\\\\F_2=12N\hat{j}\\\\F=\sqrt{(9N)^2+(12N)^2}=15N

F=15N

6 0
3 years ago
Is 250 000 miles from the earth to the moon" is a qualitative<br> Observation<br> TRUE<br> Or false
lys-0071 [83]

Answer:

True

Explanation:

3 0
3 years ago
(a) If a person can jump a maximum horizontal distance (by using a 45° projection angle) of 3.0 m on Earth, what would be his ma
emmasim [6.3K]

Answer:

See explanation

Explanation:

Range of a projectile is given by; U^2sin2θ/g

When θ = 45°

The maximum range is obtained as;

Rmax = U^2/g

Maximum range on earth = RME = U^2/g

Maximum range in the moon= RMM =U^2/g/6

Maximum range in Mars = RMMA = U^2/0.38g

a)

RME/RMM =  U^2/g/U^2/g/6

RME/RMM = 6

But RME = 3 m

RMM = 3 * 6 = 18 m

b)

RME/RMMA =U^2/g/U^2/0.38g

RME/RMMA = 1/0.38

But RME = 3 m

RMMA = 3/0.38

RMMA = 7.9 m

3 0
3 years ago
Calculate the linear momentum of photons of wavelength 350 nm. What speed does a hydrogen molecule need to travel to have the sa
lubasha [3.4K]

Answer:

a)p=1.89x10^{-27}kg.m.s^{-1}

b)v=0.565\frac{m}{s}

Explanation:

First, we need to obtain the linear momentum of the photons of wavelength 350nm.

We are going to use the following formula:

\lambda=\frac{h}{p}\\Where:\\\lambda=wavelength\\h=placnk's\_constant\\p=Linear\_momentum

So the linear momentum is given by:

p=\frac{h}{\lambda}\\\\p=\frac{6.626x10^{-34}J.s}{350x10^{-9}m}\\\\p=1.89x10^{-27}kg.m.s^{-1}

Having the linear momentum of the photon, we can calculate the speed of the hydrogen molecule to have the same momentum, we can use the classic formula for that:

p=m.v

where:\\m=mass\\v=speed\\p=linear\_momentum

The mass of the hydrogen molecule is given by:

m=2*(1.0078x10^{-3}\frac{kg}{mol}})x\frac{1}{6.022x10^{23}mol}

3.35x10^{-27}kg

What we've done here is to use the molecular weight of the hydrogen, and covert it kilograms, we had to multiply by two because the hydrogen molecule is found in pairs.

so:

v=\frac{p}{m}\\\\v=\frac{1.89x10^{-27}kg.m.s^{-1}}{3.35x10^{-27}kg}\\\\v=0.565\frac{m}{s}

3 0
4 years ago
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