The values of the number is 43
x+21=64
subtract 21 on each side
x = 43
Answer:
(x - 7)(x - 4)(x + 4).
Step-by-step explanation:
A(x) = x3 – 7x² – 16x +112
Dividing by x-7:
x^2 - 16 <-------- Quotient
-----------------------------
x-7)x^3 - 7x^2 - 16x + 112
x^3 - 7x^2
0 - 16x + 112
- 16x + 112
..............
so A(x) = (x - 7)(x^2 - 16) x^2 - 16 is the difference of 2 squares so we have:
(x - 7)(x - 4)(x + 4).
Checking by expanding the brackets:
(x - 7)(x - 4)(x + 4)
= x(x - 4)(x + 4) - 7(x - 4)(x + 4)
= x(x^2 - 16) - 7(x^2 - 16)
= x^3 - 16x - 7x^2 + 114
= x^3 - 7x^2 - 16x + 112
PEMDAS needs to be used in this case.
P is for parentheses, so we have to perform addition in parentheses first.
68+7= 75
Then, we perform the next addition:
93 + 75=168
<span>The final answer is 168</span>
Answer:
y = (x -5)² + 3.
Step-by-step explanation:
Given : parabola with a vertex at (5,3).
To find : Which equation has a graph that is a parabola.
Solution : We have given vertex at (5,3).
Vertex form of parabola : y = (x -h)² + k .
Where, (h ,k ) vertex .
Plug h = 5 , k= 3 in vertex form of parabola.
Equation :y = (x -5)² + 3.
Therefore, y = (x -5)² + 3.
Answer:
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Step-by-step explanation: