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3 years ago

Could Someone Help Me Out I Put 30 Points Out!!!!! ASAP

1 answer:

4 0

All angles on a triangle add up to 180. If it's a right triangle it would be set up like this: 90+3x-4=6x-5=180. You would subtract 90 from 180 and get 90 left. 3x-4+6x-5=90. Then you would add 5 and 4 to 90.....3x+6x=99. Then you add 3x and 6x then you would be left with 9x=99. Divide 99 by 9 and you get x=11.

You might be interested in

Match each equivalent expression with the property that it represents.

OlgaM077 [116]

Answer:

Associative Property of Multiplication

[ 3(5) (4) = (3) 5(4)]

Identity Property of Multiplication

5(1) = 5

Identity Property of Addition

(3 + 5) + 0 = (3+5)

Commutative Property of Addition

3 + 5 = 5 + 3

Associative Property of Addition

3 + (5 + 7) = (3 + 5) + 7

Step-by-step explanation:

The associative property states that you can re-group numbers and you will get the same answer and the commutative property states that you can move numbers around and still arrive at the same answer.

The identity property of 1 says that any number multiplied by 1 keeps its identity.

Hoped this helped!

6 0

3 years ago

Maggie's brother is 10 years younger than twice her age. The sum of their ages is 32.

mixas84 [53]

Answer:22

Step-by-step explanation:

5 0

2 years ago

What is the image point of (8,-3) after a translation right 5 units and down 5 units?

pshichka [43]

Answer: (13, -8)

Step-by-step explanation:

Subtract 5 from -3

Add 5 to 8

3 0

2 years ago

Which statement correctly identifies the line of reflection?

Alchen [17]

Answer:

the triangles are reflected across the line y= -x

hope this helps

Step-by-step explanation:

4 0

3 years ago

Write the equation of a circle with the following pints in the picture using the completing the square method. Thanks

pantera1 [17]

So hmm notice the picture below

you have the center, and a point on the circle... all you need is the radius

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ 3}}\quad ,&{{ -4}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\leftarrow r$

then use that radius in the circle's equation

$\bf (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad center\ ({{ h}},{{ k}})\qquad
radius={{ r}}$

8 0

3 years ago