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3 years ago

Can someone give me the value of x

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

7 0

The shape has 7 sides.

The sum of the interior angles is (7-2)180 = 5 * 180 = 900 degrees.

Divide the total sum by 7:

X = 900 /7 = 128.6 degrees.

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If f(x) = x^3 – 10x^2 + 29x – 30 and f(6) = 0, then find all<br> of the zeros of f(x) algebraically.

tino4ka555 [31]

Step 1: 1

(((x3) - (2•5x2)) + 29x) - 30 = 0

Step 2 2.1 x3-10x2+29x-30 is not a perfect cube

Step 3 Factoring: x3-10x2+29x-30

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 29x-30
Group 2: -10x2+x3

Pull out from each group separately :

Group 1: (29x-30) • (1)
Group 2: (x-10) • (x2)

7 0

2 years ago

Peter is twice the age of Sara. If their total age is 27 years. how old is Sara?

Xelga [282]

Answer:

Just do 27x2 bro simple as that

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$

a) Probability that a student has either a Visa card or a Master Card is given by,

$P(V \cup M) = P(V) + P(M) - P(V\cap M)$

$P(V \cup M) = 0.63+ 0.11- 0.03$

$P(V \cup M) =0.74- 0.03$

$P(V \cup M) =0.71$

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if $P(A\cap B)=P(A)P(B)$

For V and M to be independent the condition is satisfied,

$P(V\cap M)=P(V)P(M)$

Substitute the values,

$0.03=0.63\times 0.11$

$0.03\neq 0.0693$

So, V and M are not independent.

6 0

3 years ago

In June 2005, a CBS News/NY Times poll asked a random sample of 1,111 U.S. adults the following question: "What do you think is

Shtirlitz [24]

Answer:

The appropriate null hypothesis is $H_0: p = 0.25$

The appropriate alternative hypothesis is $H_1: p < 0.25$

Step-by-step explanation:

Exactly a year prior to this poll, in June of 2004, it was estimated that roughly 1 out of every 4 U.S. adults believed (at that time) that the war in Iraq was the most important problem facing the country.

At the null hypothesis, we test if the proportion is still the same, that is, of $\frac{1}{4} = 0.25$ . So

$H_0: p = 0.25$

We would like to test whether the 2005 poll provides significant evidence that the proportion of U.S. adults who believe that the war in Iraq is the most important problem facing the U.S. has decreased since the prior poll.

Decreased, so at the alternative hypothesis, it is tested if the proportion is less than 0.25, that is:

$H_1: p < 0.25$

3 0

3 years ago

Javier is considering two lawn care services. Premier Landscaping charges $15.00 for travel to the job site and $55.00 per hour

Wittaler [7]

Answer:

Time in which both companies charge same cost = 1.5 hour

Step-by-step explanation:

Given:

Fixed Variable

Premier Landscaping charges $15 $55

Ace Landscaping charges $65

Find:

Time in which both companies charge same cost:

Computation:

Assume in X time both companies charge same cost:

So,

Premier Landscaping total cost = Ace Landscaping total cost

⇒ $15 + $55(Time taken) = $65 (Time taken)

⇒ $15 = $65 (Time taken) - $55(Time taken)

⇒ $15 = $10 (Time taken)

⇒ Time taken = 1.5 hour

Time in which both companies charge same cost = 1.5 hour

6 0

3 years ago