The absolute value - or distance from zero, is fairly simple to find. Make your final answer positive to find it.
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
Answer:
Below in bold.
Step-by-step explanation:
In each case you divide top and bottom by the GCF.
A. The GCF of 45 and 56 is 1.
so the answer is 45/56.
B. 15/16 (GCF = 1)
C. Here the GCF is 5 so the answer is (35/5) / (80/5)
= 7/16.
D. 5/6 (GCF is 4).
SO EASY 60 people = 10 minutes in line 240 people = 40 minutes in line
Step-by-step explanation:
-8 3/8 + 6 1/4 = -2 1/8 or you can also write -17/8
<h2>hope this help you!! ;))</h2>
