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3 years ago

14

Which statement describes the congruent triangles

1 answer:

4vir4ik [10]3 years ago

3 0

Answer:

2 triangles

Step-by-step explanation:

2 triangles are said to be congruent when all the corresponding sides of the angle and the interior angles are congruent . The two triangle are said to be the mirror image of each other.

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Multiply the complex numbers (5 − 3i) and (9 + 2i).

amid [387]

The answer is

51-17i

Explanation :

5x95x2i-3ix9-3ix2i
45+10i-27i-6^2
45+10i-27i-6(-1)
45+10i-27i + 6

7 0

2 years ago

What are the coordinates of the midpoint of the segment whose endpoints are A (1,6) and B (5,-2)?

Alexandra [31]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
A(\stackrel{x_1}{1}~,~\stackrel{y_1}{6})\qquad 
B(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})
\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{5+1}{2}~~,~~\cfrac{-2+6}{2} \right)\implies (3~,~2)$

6 0

3 years ago

6.258 rounded to the nearest hundredth

Tresset [83]

<h2>Answer:</h2><h2>6.26</h2><h2></h2><h2>Hope this helps!!</h2><h2 />

5 0

2 years ago

Read 2 more answers

1.) Solve x - 9 = -12<br>-) Solve 2t + 7 = -1

Harlamova29_29 [7]

Answer:

1)x=3

2)t=-4

Step-by-step explanation:

x-9=-12

x=3

2t=-8

t=-4

8 0

2 years ago

Read 2 more answers

In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad

zysi [14]

Answer: a) 0.0792 b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)$ (1)

Similarly ,

$P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792$

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

$P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264$

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0

2 years ago