In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
The circumference of the circle
is given by the equation C = pi * D. Incorporating the length of the diameter
into the equation, we have,
C = pi * D
C =
pi * 7cm
C =
21.99 cm
Answer:
D
Step-by-step explanation:
intercept is -4 and slope is rise over run which is 3/1 = 3
put into slope intercept form to achieve answer D
Answer: 3
Step-by-step explanation:
simply divide 1200 by 400. :)
X=-8
A negative plus a positive, if ghe negative is bigger it stays negative. -8 is bigger than 5 and 8 - 5 is 3 add the negative and you get -3
