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2 years ago

I have 3 questions.

1 answer:

mote1985 [20]2 years ago

8 0

Similar triangles are scales drawing of one another is true, what is the slope of this equations is undefined, to what line equation does the points are solution of sets are,35 the answer

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Write an expression in simplest form that represents the perimeter of the polygon

scoundrel [369]

Answer:

Perimeter = (11x + 12)

Step-by-step explanation:

Since, perimeter of a polygon is represented by the sum of measures of all sides,

Perimeter of the given polygon = 3x + (x + 10) + 5x + (2x + 2)

By adding like terms of the expression,

Perimeter of the polygon = (3x + x + 5x + 2x) + (10 + 2)

= (11x + 12)

Therefore, expression for the perimeter is (11x + 12).

6 0

2 years ago

Help??? Its a two step inequality problem. I dunno what X equals too.

Verizon [17]

Answer:

$x \geq -1$

Step-by-step explanation:

$-4x + 2 \geq -6x$

Add $6x$ to both sides:

$-4x + 2 + 6x \geq -6x + 6x$

$2x + 2 \geq 0$

Subtract 2 from both sides:

$2x + 2 - 2 \geq 0 - 2$

$2x \geq -2$

Divide both side by 2:

$\frac{2x}{2} \geq \frac{-2}{2}$

$x \geq -1$

5 0

2 years ago

Read 2 more answers

A grain silo has a circular base with an area of 260 square feet and is 21 feet tall What is the total volume?

Leya [2.2K]

The correct answer is 5460 cubic feet or 5460 $ft^{3}$

Explanation:

The silo has a cylindrical shape, in this context, the volume of the silo or any other cylinder can be calculated by using the formula $Volume =\pi r^{2} h$ . In this formula the symbol $\pi$ refers to the number 3.1415..., the letter $r$ refers to the radius of the base and the letter $h$ refers to the height.

Moreover, in this case, it is known the heigh (21 feet) and the area of the base (260 square feet). Additionally, this area of the base is the result of the formula $Area = \pi r^{2}$ , which is exactly the first section of the formula to find the volume. This implies that by multiplying the area of the base by the height the volume is known. Here is the process:

$Volume = \pi r^{2} h$ or $Volume = Ah$ (Area of the base × height)

$V = 260 square feet$ × $21 feet$

$V = 5460 cubic feet$

6 0

2 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago

write about which method you prefer to use to divide by 5 counting up, counting back on a number line, or dividing by 10, and th

maria [59]

Answer:

In First method : counting up, counting back on a number line,

If we want the quotient after dividing the number by 5 then we count how many 5 we get from 0 to the dividend.

For example : $\frac{30}{5}$

Since, from 0 to 30 there are six 5's obtained. ( because 5 × 6 = 30 )

Thus, $\frac{30}{5}=6$

In Second Method : dividing by 10, and then doubling the quotient.

First we divide the number by 10 then multiply the quotient by 2.

For Example: $\frac{30}{5}$

Since, $\frac{30}{10}=3$

$2\times 3 = 6$

Thus, $\frac{30}{5}=6$

Now, when we compare the above methods then we conclude that for the smaller numbers first method is appropriate because for small numbers we can easily count total 5's from 0. While for large numbers Second method is appropriate because it is hard to count the total 5's for the large number.

4 0

2 years ago

Read 2 more answers