The correct answer for the question that is being presented above is this one:
We need to express the ksp expression of C2D3
<span>C2D3
= (2x)2(3x)3
= 108x5 </span>
<span>Then set that equation equal to your solubility constant </span>
<span>9.14x10-9 = 108x5 </span>
<span>x = 9.67x10-3
</span>
<span>So the molar solubility is 9.67x10-3</span>
The distance formula is:
We are given two points in the form (x,y), so plug in the values to the distance formula:
Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:
The square and square root cancel each other out leaving us with 25.
The answer is 25.
The smallest is 6
Three consecutive integers
X. Smallest 6
X+1. 7
X+2. Largest 8
X(X+1)= 4(X+2)+10
X^2+X= 4x+8+10
X^2+X-4x-18=0
X^2-3x-18=0
( X+3)(X-6)
X=-3. X=6
Don't use the negative
Check 6(7)= 4(8)+10
42=42
Answer:
The answer is 20 degrees
Step-by-step explanation:
A trapezoid is a quadrilateral with four angles and the sum of the four angles is 360 degrees.
Britton rotated the trapezoid ABCD 180º, but we were not told that he tampered with the angles size or shape, we can now agree that it is still the same trapezoid that was rotated without any alterations in angles, size and shape.
Since we've been given that the angle B is 20º, and the measurement was not altered when rotating the trapezoid. Therefore the angle B' will also be 20º.
I hope this helps.
Answer: He needs a minimum of 2011.25 hours
Step-by-step explanation:
In order for Gavin to get his private pilot certificate he must fly solo.
He must fly a minimum of 2020 hours with his plane instructor before he can fly solo.
He has already flown 8 3/4 hours with his instructor. This is express as 8hours + (3/4 × 1) = 8.75 hours
To determine how many more flying hours that he needs before he can fly solo, we will subtract the number of hours that he had flown from the the minimum of 2020 hours . it becomes
2020 - 8.75 = 2011.25.
He needs a minimum of 2011.25 hours
