19. What you know is that HK+KJ = HJ. If HJ = 25, the sum of the two equations will equal this length.
x-5+5x-12=25 First, combine your like terms. You will end up with 6x-17=25. Add the opposite of -17 to both sides. 6x = 42 Divide both sides by 6. x = 7. Substitute x=7 for your original expression of x-5, 7-5=2
20. (5x-6)/2 = x+6 Multiply each side by 2. 5x-6 = 2x +12 Add 6 to each side 5x = 2x + 18 then subtract 2x from both sides as well. 3x = 18 Finally divide each side by 3. x=6 To find the length of the remaining segment, substitute this value into (5x-6)/2. This results in each side equaling a distance of 12.
21. On the number line, the distance of FG is 16 units. If the distance of FP is 1/4 of FG, you would simply divide 16 by 4. The distance of FP is 4 and P lies at 8 on your number line.
23. The distance of SP is x+4 and ST=4x. Since P is the midpoint, you only have one half of the line as x+4, if you were to double it, you would find that 2x+8 = 4x. Balance and solve for x, subtract 2x from both sides. 8=2x Divide each side by 4, 8/4 = 4x/4 resulting in x=2. If ST equals 4x, substitute and solve, 4(2) = 8
Answer:
BD
AC
SN (might not be one)
AB
Step-by-step explanation:
The angles in an equilateral triangle are 60 degrees.
sin 60 = 9 / h where h is hypotenuse ( = side of the triangle)
h = 9 / sin 60 = 10.392
Perimeter = 3 * h = 31.18 to nearest hundredth
Answer:
1. b=39.497
2. c=3.606
3. a=18.974
Step-by-step explanation:
1.
41^2-11^2=b^2
1681-121=b^2
b^=1560
b=39.497
2.
2^2+3^2=c^2
4+9=c^2
c^2=13
c=3.606
3.
21^2-9^9=a^2
441-81=a^2
a^2=360
a=18.974
