Answer:
f(x) = g(x) at x=0 and x=1. The value of f(1)=g(1) is 3.
At x=3, the function values are somewhat different.
Step-by-step explanation:
The points of intersection of the two functions are (0, 1) and (1, 3). One needs to pay attention to the question being asked and how these points relate to the answer.
Generally, when we're solving f(x)=g(x), we're only concerned with the values of x that make the equation true. When you graph both f(x) and g(x) and look for points of intersection, you also find the "y" values at which the equation is true. (If you graph f(x)-g(x) and look only for x-intercepts, there is no such issue.)
Answer:
To show that an equation is an identity: Start with either side of the equation and show that it can algebraically be changed into the other side. Or start with both sides of the equation and show that they both can be changed into the same algebraic expression.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Generally equation of a line is given as
y=mx+c
Then given the point (x, y)=(0,2)
Therefore x=0 and y=2
y=mx+c
2=m×0+c
2=0+c
Then, c=2
Then intercept is 2
Also given the point (x, y)=(3,4)
x=3 and y=4 and c=2
y=mx+c
4=m×3+2
4=3m+2
4-2=3m
2=3m
Then, m=2/3
Then, the slope of the graph is 2/3
y=mx+c
Now, m=2/3 and c=2
The general equation of the line becomes
y=2/3x+2
Multiply through by 3
3y=2x+6
Then this is the equation of the line
(x + 2y)^10
(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)
(x² + 4xy + 4y)(x² + 4xy + 4y)(x² + 4xy + 4y)(x² + 4xy + 4y)(x² + 4xy + 4y) (x^4+8x³y+8x²y+16x²y²+20xy²+16y²)(x^4+8x³y+8x²y+16x²y²+20xy²+16y²)(x²+4xy+4y)
slope = y2-y1 / x2-x1=
-1 -5 / 2 - -1 = -6/3 = -2
slope = -2
y intercept = y =mx +b
y = -2x +b
y=-2*-1 +b
5 = -2 +b
b = 5-2
b =3
y intercept = 3