It depends on the variable.
If it's something like x < 2, your graph would be a vertical line at x = 2, and everything to left of that line shaded in (because of the less than).
Similarly for y, except it would be a horizontal line with either everything above or below shaded.
You can have other equations like 0<x<4 where everything between x = 0 and x = 4 would be shaded
Hello!
Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1.
A) x-axis, y=x, y-axis, x-axis
b) x-axis, y-axis, x-axis
c) y=x, x-axis, x-axis
d) y-axis, x-axis, y-axis, x-axis
The best answer is C180 rotation wud take that point to 4th quadrant
reflection in x-axis takes that to 1st quadrant
<span>reflection in y-axis brings it back to 2nd quadrant again. So, the sequence of transformations will bring A back to where it started
</span>
Hope this Helps! :)
Answer:
49π
Step-by-step explanation:
A = π 
A = π 
A = 49π
For the one you put in the comment...
The radius of a circle is 19cm find its area in terms of π
A = π
A = π 1
A = 361π
For the other one you put in the comment
The radius of a circle is 4 cm find its area in terms of π
A = π
A = π 
A = 16π
For the other one you put in the comment
The radius of a circle is 20 cm find its area in terms of π
A = π
A = π 
A = 400π
Hope this helped!
Have a supercalifragilisticexpialidocious day!
