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Brilliant_brown [7]
3 years ago
11

HELP AFAP Please help its important I'll make you brainlist

Mathematics
1 answer:
just olya [345]3 years ago
6 0

Answer:

Step-by-step explanation:

i had this question

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25 points and if possible brainiest if correct.
vampirchik [111]

Answer:

7

Step-by-step explanation:

7

4 0
2 years ago
Rambo-Conduit Corporation manufactures plastic conduit that is used in the cable industry. A conduit is a tube that encircles an
DIA [1.3K]

Answer:

The resin materials cost per foot of finished product for June is $0.53

Option a) $0.53 is the right answer

Step-by-step explanation:  

Given the data in the question;

                                                       May                  June                          uly

Resin pounds input

into the process                        470,000            700,000                 650,000  

Price per pound                         X$1.50               X$1.50                    X$1.50

Plastic material costs             $493,000         $640,000                 $677,000

Conversion costs                    $80,000           $120,000                 $115,000

Conduit output from

the process (feet)                   800,000           1,200,000                 1,130,000

Assuming that there is one-half pound of resin per foot of the finished product, determine the resin materials cost per foot of finished product for June.

Now;  

Materials cost for June = $640,000

Number of Feet produced as output in June =  1,200,000    

so

Material Cost per feet of finished product will be;

= $640,000 / 1,200,000

= $0.5333 ≈ $0.53

Therefore, the resin materials cost per foot of finished product for June is $0.53

Option a) $0.53 is the right answer

7 0
2 years ago
In the football game, a penalty of -15 yards was applied to a gain of 43 yards. What was the net gain?
Stella [2.4K]

Answer:

c

Step-by-step explanation:

28

7 0
3 years ago
Which of the following equations could be th equation to represent the given graph? Make sure you explain your answer thoroughly
Alex17521 [72]

Answer:

Option (C) is correct.

Step-by-step explanation:

The given options of the possible equation for the graph are as follows:

(A) y=2\left(\frac{3}{2}\right)^x \\\\(B) y=-2\left(\frac{3}{2}\right)^{-x} \\\\(C) y=2\left(\frac{2}{3}\right)^x \\\\(D) y=-2\left(\frac{2}{3}\right)^{-x} \\\\

The given graph is decreasing and at x=0, y=2.

So, first checking the value of the given options for x=0

(A) y=2\left(\frac{3}{2}\right)^0=2\times 1= 2 \\\\(B) y=--2\left(\frac{3}{2}\right)^{-0}= -2\times 1= -2 \; (not\; possible) \\\\(C) y=2\left(\frac{2}{3}\right)^0= 2\times 1= 2 \\\\(D) y=2\left(\frac{2}{3}\right)^{-0} = -2\times 1= -2 \; (not\; possible)

As, for x=0, y=2, so options (C) and (D) are not possible, so rejected.

Now, checking the nature (increasing or decreasing) of the given equation by differentiating it.

For option (A),

\frac{dy}{dx}=2\left(\frac{3}{2}\right)^{x}\times \ln\left(\frac{3}{2}\right)

As \ln \left(\frac{3}{2}\right)=\ln(1.5)>0 \;and\; \left(\frac{3}{2}\right)^{x} >0

So, \frac{dy}{dx}>0

Therefore, the function in option (A) is increasing function.

Similarly, for option (C),

\frac{dy}{dx}=2\left(\frac{2}{3}\right)^{x}\times \ln\left(\frac{2}{3}\right)

As \ln \left(\frac{2}{3}\right)=\ln(0.67)0

So, \frac{dy}{dx}

Therefore, the function in option (C) is decreasing function.

As the given graph is decreasing, so, (C)  representsy=2\left(\frac{2}{3}\right)^x the given graph.

Hence, option (C) is correct.

6 0
3 years ago
What is the solution to the equation 4x - 6 = 10x - 3?
beks73 [17]

\huge{\boxed{\tt{Solution:-}}}

<h3><u>Given :</u></h3>
  • \sf {4x-6=10x-3}
<h3><u>T</u><u>o</u><u> </u><u>Find</u><u> </u><u>:</u></h3>
  • What is the solution of the equation:

\sf{(a.)\:x=\dfrac {-1}{2}}

\sf{(b.)\:x=-2}

\sf{(c.)\:x=\dfrac {1}{2}}

\sf{(d.)\:x=2}

Now, we solving it :

\sf{: \implies  {4x - 6 = 10x - 3}} \\  \\ \sf{: \implies  { - 6 + 3= 10x - 4x}} \\  \\ \sf{: \implies  { - 3= 6x}} \\  \\ \sf{: \implies  {  \dfrac{- 3}{6} = x}} \\  \\ \sf{: \implies  {\dfrac{- 1}{2} = x}} \\  \\  : \implies  {\boxed{ \sf{x =\dfrac{- 1}{2}}}}

\bf{\therefore{Correct \:solution\:is\:(a.)\:x=\dfrac {-1}{2}.}}

\rule {307}{2}

5 0
3 years ago
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