A cannonball is shot straight up into the air. The height of the cannonball at time t is represented by the function f(t)=−16t^2

Question

3 years ago

8

A cannonball is shot straight up into the air. The height of the cannonball at time t is represented by the function f(t)=−16t^2

+40t+5 .
What does the 5 represent?

the maximum height of the cannonball

the initial height of the cannonball

the time when the cannonball hits the ground

the initial velocity of the cannonball

Mathematics

1 answer:

Karo-lina-s [1.5K] · Answer 1 · 2022-09-11T12:30:52+03:00

Answer:

the initial height of the cannon ball

Step-by-step explanation:

- Time (t) is basically how many seconds or minutes you factor into the given function. 16(time in exact seconds or minutes)^2+40(time in exact seconds or minutes) +5

- The +5 can only be where the cannonball was initially fired from logically. The Velocity formula is already there for you to plug the time into^^^

(I used time in minutes/seconds to try and explain what the function is asking)