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Orlov [11]
3 years ago
7

The graph shows the relationship between James’s resting heart rate and the number of hours he exercises per day. For every hour

of exercise, James’s resting heart rate decreases by about (1,5,15,20) beats per minute. His resting heart rate is about (50.5, 70, 77.5,82.5) beats per minute when he exercises 4 1/2 hours a day.

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0

Answer:

decreases by about 5 beats per minute

His resting heart beat is about 80 beats per minute

Step-by-step explanation:

sweet-ann [11.9K]3 years ago
6 0

Answer:

dude im in 8th grade and im getting college math no wonder i have a D-

Step-by-step explanation:

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Step-by-step explanation:

I hope that it's a clear solution.

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NeX [460]

Answer:

\displaystyle \frac{dy}{dx} \bigg| \limit_{(1, 4)} = 2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Coordinates (x, y)
  • Exponential Rule [Root Rewrite]:                                                                 \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}
  • Exponential Rule [Rewrite]:                                                                           \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Implicit Differentiation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle \sqrt{x} - \sqrt{y} = -1

Point (1, 4)

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                               \displaystyle x^{\frac{1}{2}} - y^{\frac{1}{2}} = -1
  2. [Implicit Differentiation] Basic Power Rule:                                                 \displaystyle \frac{1}{2}x^{\frac{1}{2} - 1} - \frac{1}{2}y^{\frac{1}{2} - 1}\frac{dy}{dx} = 0
  3. [Implicit Differentiation] Simplify Exponents:                                               \displaystyle \frac{1}{2}x^{\frac{-1}{2}} - \frac{1}{2}y^{\frac{-1}{2}}\frac{dy}{dx} = 0
  4. [Implicit Differentiation] Rewrite [Exponential Rule - Rewrite]:                   \displaystyle \frac{1}{2x^{\frac{1}{2}}} - \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = 0
  5. [Implicit Differentiation] Isolate <em>y</em> terms:                                                       \displaystyle -\frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = -\frac{1}{2x^{\frac{1}{2}}}
  6. [Implicit Differentiation] Isolate \displaystyle \frac{dy}{dx}:                                                               \displaystyle \frac{dy}{dx} = \frac{2y^{\frac{1}{2}}}{2x^{\frac{1}{2}}}
  7. [Implicit Differentiation] Simplify:                                                                 \displaystyle \frac{dy}{dx} = \frac{y^{\frac{1}{2}}}{x^{\frac{1}{2}}}

<u>Step 3: Evaluate</u>

  1. Substitute in point [Derivative]:                                                                     \displaystyle \frac{dy}{dx} = \frac{(4)^{\frac{1}{2}}}{(1)^{\frac{1}{2}}}
  2. Exponents:                                                                                                     \displaystyle \frac{dy}{dx} = \frac{2}{1}
  3. Division:                                                                                                         \displaystyle \frac{dy}{dx} = 2

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

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