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3 years ago

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A. A school has 700 students. If 2 out of every 5 students are high school students, how many high school students are there at

the school?
B. If each highschool student spends 279.50 minutes in a school a day, how many total minutes do the high school students spend in class each day?

Extension: If the average middle schooler spends 10 percent more time in class than the average highschooler, how much time do the middle schoolers spend in class a day?

1 answer:

siniylev [52]3 years ago

5 0

Answer:

280 students

78260 minutes

307.45 minutes per day

Step-by-step explanation:

A We multiply the total number of students by the fraction that are high schoolers to determine the total number of high schoolers

700 * 2/5 = 280

There are 280 high schoolers

B The total time high schoolers spend in school is the time 1 student spends in school times the number of students

279.5 * 280 =78260 minutes

C The high schoolers spends 279.5 minutes in class

10% = .1

We need to add 10% to this time

279.5 * 10%

279.5 * .1 = 27.95

Add this because they spend 10% more time

279.5 + 27.95 =307.45 minutes

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What’s the mean absolute deviation of 103,171,115,165,124,170,125

Sholpan [36]

ANSWER: The mean absolute deviation of the pattern given is: 25.428571.

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2 years ago

Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .

tankabanditka [31]

Answer:

Slope of a tangent to the curve = $f'(x) = \frac{-1 }{(x+1)^{2} }$

Step-by-step explanation:

Given - y = 1/x+1

To find - Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .

Proof -

We know that,

Slope of tangent line = f'(x) = $\lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$

We have,

f(x) = y = $\frac{1}{x+1}$

So,

f(x+h) = $\frac{1}{x+h+1}$

Now,

Slope = f'(x)

And

$f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \\= \lim_{h \to 0} \frac{\frac{1}{x+h+1} - \frac{1}{x+1} }{h}\\= \lim_{h \to 0} \frac{x+1 - (x+h+1) }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{x +1 - x-h-1 }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-h }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-1 }{(x+1)(x+h+1)}\\= \frac{-1 }{(x+1)(x+0+1)}\\= \frac{-1 }{(x+1)(x+1)}\\= \frac{-1 }{(x+1)^{2} }$

∴ we get

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6 0

3 years ago

27 divided by 53 minus 6 plus 53 times -2 squared

mamaluj [8]

Answer:

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\left(-\left(2^2\right)\right)\right)=-\frac{11527}{53}\quad \left(\mathrm{Decimal:\quad }\:-217.49056\dots \right)$

Step-by-step explanation:

Considering the expression

27 divided by 53 minus 6 plus 53 times -2 squared

Which can be written as

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\cdot \left(-\left(2^2\right)\right)\right)$

So, solving the expression

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\cdot \left(-\left(2^2\right)\right)\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\frac{27}{53}-6-53\cdot \:2^2$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:6=\frac{6\cdot \:53}{53}$

$=-\frac{6\cdot \:53}{53}+\frac{27}{53}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-6\cdot \:53+27}{53}$

$=\frac{-291}{53}$ ∵ $-6\cdot \:53+27=-291$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-2^2\cdot \:53-\frac{291}{53}$

$=-212-\frac{291}{53}$ ∵ $53\cdot \:2^2=212$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:212=\frac{212\cdot \:53}{53}$

$=-\frac{212\cdot \:53}{53}-\frac{291}{53}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-212\cdot \:53-291}{53}$

$=\frac{-11527}{53}$ ∵ $-212\cdot \:53-291=-11527$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{11527}{53}$

Therefore,

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\left(-\left(2^2\right)\right)\right)=-\frac{11527}{53}\quad \left(\mathrm{Decimal:\quad }\:-217.49056\dots \right)$

Keywords: algebraic expression

Learn more about solving algebraic expression from brainly.com/question/4687406

#learnwithBrainly

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4 years ago

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area of the shaded region = area of the outer circle - area of the inner circle

= πR²-πr²

=π(R²-r²)

=π{(6.5)²-(2.3)²}

=π (42.25-5.29)

= 3.14× 36.96

= 115.866

= 116 cm²

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3 years ago

What is the mean of the following data values 53,71, 89,10,87

lesya692 [45]

Well the way you would do it is you would add all of them up and then divide them by how much there is so the numbers added up give you 310 divided by 5 is 62 hop this helps!!!

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4 years ago

Read 2 more answers