3ab - 3a - 8 + 4ab + 8
7ab -3a
Answer:
c= 3
Step-by-step explanation:
0.2(10 -5c)= 5c -16
<em>Expand</em><em>:</em>
0.2(10) +0.2(-5c)= 5c -16
2 -c= 5c -16
<em>Bring</em><em> </em><em>all</em><em> </em><em>c</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>,</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em>:</em>
5c +c= 2 +16
<em>Simplify</em><em>:</em>
6c= 18
<em>Divide</em><em> </em><em>by</em><em> </em><em>6</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
c= 18 ÷6
c= 3
Answer:
4/9 or 44.44%
Step-by-step explanation:
We have the following probabilities:
Probability of winning the statistical test = P (s) = 2/3
Probability of winning the mathematics and statistics test = P (s n m) = 14/45
Probability of winning at least one test = P (s u m) = 4/5
We have that, the probability of winning the mathematics test P (m) can be found in the following way:
P (s n m) = P (s) + P (m) - P (s u m)
replacing we have:
14/45 = 2/3 + P (m) - 4/5
P (m) = 14/45 - 2/3 + 4/5
p (m) = 4/9 = 0.444
Which is the same as there is a 44.44% probability that I will win the math test
Step-by-step explanation:
I don't know the answer to that.
The sum of two consecutive even integers is at most seven more than half the sum of the next two consecutive even integers
two consecutive even integers: n, n+2
next two consecutive even integers n+4, n+6
n+(n+2) >= 7+1/2(n+4 +n+6)
combine like terms
2n+2 >= 7 +1/2(2n+10)
distribute 1/2
2n+2 >= 7+n+5
2n+2>= n+12
subtract n from each side
n+2>= 12
subtract 2 from each side
n>10
4 integers : 10, 12 ,14, 16
