Hi There! :)
Jay, Kay, and Ray found themselves far apart when they stopped for lunch while walking in a field. Jay could see Kay, then turn through 75th, and couldsee Ray. Jay could see Ray, then turn through 50th amd see Jay. Ray could see Jay, the turn through 55th, and see Kay. Which two were the farthest apart?
A. Kay and Ray
B. Jay and Kay
C. Ray and Jay
D. Kay and Ray were the same distance apart as Ray and Jay
I believe it's <span>A. Kay and Ray</span>
Answer:
<em />
<em />
<em />
Step-by-step explanation:
Given
Represent the probability that a student has a phone with p

Required
Determine the probability that 10 has
This is calculated as thus:

Where n = 10



<em />
<em> --- Approximated</em>
Answer:
I believe it's the first option because the y-intercept is -7
Step-by-step explanation:
Number is number is -14 or -26
Answer:

And we know that the value for the west side is 
So then if we solve for x from the last equation we got:

So then the east side is about
long
Step-by-step explanation:
For this problem we know that the east side of Mrs. Hammond's ranch is 455 meters longer than the west side. Let's say that the east side is x and the west is y so we have this formula:

And we know that the value for the west side is 
So then if we solve for x from the last equation we got:

So then the east side is about
long