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PSYCHO15rus [73]
3 years ago
8

7. Suppose that y varies inversely with x. Write an equation for the inverse variation,

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

The answer is

<h2>y =  \frac{24}{x}</h2>

Step-by-step explanation:

The statement

y varies inversely with x is written as

y =  \frac{k}{x}

where k is the constant of proportionality

To find k substitute the values of x and y into the equation

From the question

y = 4

x = 6

We have

4 =  \frac{k}{6}

Cross multiply

k = 4 × 6

k = 24

So the formula for the variation is

<h2>y =  \frac{24}{x}</h2>

Hope this helps you

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Each of 8 students reported the number of movies they saw in the past year. This is what they reported:
elena-14-01-66 [18.8K]

Answer:

10.75

11

Step-by-step explanation:

the mean is the average, so add up all of the values and divide by 8 because there are 8 values :

(11 + 17 + 14 + 11 + 4 + 7 + 11 + 11)/8 = 10.75

the median is the middle value when the numbers are written in ascending or descending order :

4, 7, 11, 11, 11, 11, 14, 17

we can cross out the values on the ends, to get to the middle. if we do this, we are left with 11, 11

find the average of these numbers :

which is 11.

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All you can do to this expression is simplify.

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6q + 1q = 7q

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Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
lidiya [134]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

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Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

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Answer:

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