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Ilya [14]
1 year ago
11

CAN SOMEONE PLS HELP ME W THIS PROBLEM I NEED HELP ASAP

Mathematics
1 answer:
denis-greek [22]1 year ago
6 0

The blank spaces about the passage can be filled with the following correct vocabulary respectively.

  • inequality
  • strict inequality
  • compound inequality
  • solution sets
  • true

<h3>Inequality</h3>

An <u>inequality</u> is a relation between two numbers and/or expressions that are related via <, >, ≥ or ≤ sign.

A <u>strict inequality</u> is an expression that uses < and >. It tells us that one side is only more or less than the other side.

When 2 simple inequalities are joined by or and, we get a <u>compound inequality</u>.

When solving an inequality, the solution will be a range of values called its <u>solution sets</u>. The inequality will remain <u>true</u> for every single value in this range.

The inequality signs are;

  • Greater than >
  • Less than <
  • Greater than or equal to ≥
  • Less than or equal to ≤
  • Equal to =

Learn more about inequality:

brainly.com/question/25275758

#SPJ1

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Answer:k=1,k=-2,k=8\pm 5\sqrt{3}

Step-by-step explanation:

Given two vectors

u=1\hat{i}+k\hat{j}

v=2\hat{i}+1\hat{j}

\left ( i\right )Distance between them is given by

|u-v|=\sqrt{\left ( 2-1\right )^2+\left ( 1-k\right )^2}=1

squaring both side

1^{2}+\left ( 1-k\right )^2=1

k^2-2k+1=0

\left ( k-1\right )^2=0

k=1

\left ( ii\right )

angle between u and v is 90 i.e. orthogonal

u\dot v=0

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2+k=0

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angle between u & v is \frac{\pi }{3}

u\dot v=|u||v|cos\left (\frac{\pi }{3}\right )

|u|=\sqrt{1^2+k^2}

|v|=\sqrt{2^2+1^2}

2+k=\left ( \sqrt{1+k^2}\right )\left ( \sqrt{5}\right )cos\left ( \frac{\pi }{3}\right )

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