There are four nitrogenous bases that makes DNA. These are A, T, G and C. If a DNA strand has eight pairs of nitrogenous bases, the eight bases can be
1. AA GG TT CC
2. GC GG AT CG
3. AT TA GG GC
4. GA AG GC GG
Like this, there can be 65,536 different sequences with ATCG.
Since we have 4 nitrogenous bases, pairing will make 4 X 4 = 16 combinations. If we have to make 8 pairs of bases, the number of possible sequences would be 4 to the power 8.
Answer: THERE WILL BE 65,536 DIFFERENT SEQUENCES OF 8 BASES.
I think you wrote this wrong? Is it not round rr vs wrinkled RR?? I'll answer it with that assumption:
You are crossing a rr with an RR:
You only get Rr back so they will phenotypically be all wrinkled
If you are crossing rr with an Rr (so a heterozygote wrinkled):
50% will be Rr (wrinkled)
50% will be rr (round)
See my picture for the Punnett Squares for both answers!
Answer:
Sprouting
Explanation:
process of seed germination, water is absorbed by the embryo, which results in the rehydration and expansion of the cells.
hope this helps
The correct answer is B. competitive exclusion.
This law refers to the fact that it is nearly impossible for two species to exist in the same place at the same time together, if they are interested in the same resources. If both species need the same thing to survive, one will have to be stronger while the other one will dwindle in number.