We can use the formula y2-y1/x2-x1 to find the answer. Therefore, we would have: 6-(-6)/-2-x equalling -3. So, 12/-2-x = -3. We multiply both sides by -2-x and get 12 = -3(-2 - x), then 12 = 6+ 3x. We then get 6 = 3x, and by dividing both sides by 2 we get x = 2.

6 0

2 years ago

Will give brainliest!!

swat32

Answer:

its 5 hours i think

Step-by-step explanation:

3 0

3 years ago

Evaluate. 75-2(9-5)²+2³

Andreyy89

$75-2(9-5)^2+2^3$

First, solve the parentheses:

$75-2(4)^2+2^3$

Next, the exponential terms

$75-2(16)+8$

Solve the multiplication:

$75-32+8$

Add and subtract:

$51$

5 0

1 year ago

20 points! Will mark the brainliest!

andrew-mc [135]

$\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }$

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Write the divide fraction horizontally:
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$= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}$

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Factorise the numerators and denominators when possible:
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$= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}$

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Convert the divide fraction to multiplication fraction
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$= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}$

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Cancel the factors
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$= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}$

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Combine to single fraction
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$= \dfrac{1}{4(x+2)^2}$

4 0

3 years ago