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elena55 [62]
3 years ago
5

Whats the answer for (5x + 8)(4x² + 6x - 8)

Mathematics
1 answer:
mestny [16]3 years ago
4 0
(5x + 8)(4x^2 + 6x - 8)\\ \\ 5x(4x^2 + 6x - 8) + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 32x^2 + 48x - 64 \\ \\ 20x^3 + (30x^2 + 32x^2) + (-40x + 48x) - 64 \\ \\ 20x^3 + 62x^2 + 8x - 64 \\ \\

The final result is: 20x^3 + 62x^2 + 8x - 64.
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Given h(x) = 5x + 2, solve for 2 when h(x) = -8.
san4es73 [151]

Answer:

\huge\boxed{\sf x = -2}

Step-by-step explanation:

\sf h(x) = 5x+2\\\\Put \ h(x) = -8\\\\-8 = 5x+2\\\\Subtract \ 2 \ to \ both \ sides\\\\-8-2 = 5x\\\\-10 = 5x\\\\Divide\ both \ sides \ by \ 5\\\\-10 / 5 = x \\\\x = -2 \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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