Answer:
161.8cm²
Step-by-step explanation:
solve for height which is the opposite
opp=x
sin(theata)= opp./hyp.
sin23=x/30
x=30×sin23
x=11.72cm
height=opposite
height=11.72cm
base=adjacent
base=27.6cm
½of 27.6cm=13.8
13.8cm×11.72cm=161.74 (2d.p)
161.74 rounded to the nearest tenths= 161.7
I'm not sure if it's the answer but it's the closest thing to the options
Answer:
first of all,
Step-by-step explanation:
In triangle ABC one side equal and two sides equal
Step-by-step explanation:
We are given a prism whose base is square with sides 8 in and height 12 in.
If we take cross section through vertices A, B and C
We will get a cross section as triangle.
In triangle ABC, sides are AB, BC and AC
AB is diagonal of top square whose side 8 in.
AC is face diagonal of front face.
BC is face diagonal of right face.
AC=BC≠AB
Hence, In triangle ABC one side equal and two side equal
Hope this helps!!
Answer:
Option C
Step-by-step explanation:
We are given a coefficient matrix along and not the solution matrix
Since solution matrix is not given we cannot check for infinity solutions.
But we can check whether coefficient matrix is 0 or not
If coefficient matrix is zero, the system is inconsistent and hence no solution.
Option A)
|A|=![\left[\begin{array}{ccc}4&2&6\\2&1&3\\-2&3&-4\end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%262%266%5C%5C2%261%263%5C%5C-2%263%26-4%5Cend%7Barray%7D%5Cright%5D%20%3D0)
since II row is a multiple of I row
Hence no solution or infinite
OPtion B
|B|=![\left[\begin{array}{ccc}2&0&-2\\-7&1&5\\4&-2&0\end{array}\right] \\=2(10)-2(10)=0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%260%26-2%5C%5C-7%261%265%5C%5C4%26-2%260%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2810%29-2%2810%29%3D0)
Hence no solution or infinite
Option C
![\left[\begin{array}{ccc}6&0&-2\\-2&0&6\\1&-2&0\end{array}\right] \\=2(36-2)=68](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%260%26-2%5C%5C-2%260%266%5C%5C1%26-2%260%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2836-2%29%3D68)
Hence there will be a unique solution
Option D
![\left[\begin{array}{ccc}5&10&5\\4&1&4\\-1&-2&-1\end{array}\right] \\=2(10)-2(10)=0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%2610%265%5C%5C4%261%264%5C%5C-1%26-2%26-1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2810%29-2%2810%29%3D0)
=0
(since I row is -5 times III row)
Hence there will be no or infinite solution
Option C is the correct answer
Step-by-step explanation:
x2 + 7x + 12
x2 + 4x + 3x + 12
x(x + 4) + 3( x + 4)
(x + 3) and (x + 4) are the factors
4x2 + 6x + 2
4x2 + 4x + 2x + 2
4x (x + 1) + 2(x + 1)
(x + 1) and (4x + 2) are the factors
Answer:
1 and 2/3
Step-by-step explanation:
5/3 = 1 and 2/3 * 1 = 1 and 2/3
