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tia_tia [17]
3 years ago
15

Whats the equation of this Circle?

Mathematics
2 answers:
Leviafan [203]3 years ago
7 0

So the answer is this

-2+-7=-5

Kaylis [27]3 years ago
7 0

equation of a circle is given as

(x-a)^2 + (y-b)^2 = r^2

where (a,b) is coordinates of center of the circle and r is radius.

as per shown in graph we can see center of circle.is ( -7, -2)

now let's calculate radius. we have to calculate distance between any point on circle and center . let's take point (-7,0) on the circle shown in graph.

r = √((-7-(-7))^2 + (0-(-2))^2

r = √4 = 2

so equation is

(x -(-7))^2 + (y - (-2))^2 = 2^2

(x +7)^2 + (y +2)^2 = 4

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qaws [65]

Answer:

\frac{x^2+2x}{x-3}

Step-by-step explanation:

We need to factor out numerator and denominator in order to simplify the rational expression by cancelling  common factors.

Numerator :  x^3 - 4 x = x (x^2 - 4) = x (x - 2) (x + 2)

Denominator (factoring by grouping):

x^2 - 5 x + 6 = x^2 - 3 x - 2 x + 6 = x (x - 3) - 2 (x - 3) = (x - 3) (x - 2)

Then we can cancel out the common factor (x - 2) in both numerator and denominator, leading to:

x (x + 2) / (x - 3) = (x^2 + 2)/ (x-3)

\frac{x^2+2x}{x-3}

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3 years ago
NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.​
slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

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\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

Total surface area:

\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

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\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

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\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

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Sveta_85 [38]
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56 - 54 6/11= 1 5/11
7 0
3 years ago
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Marianna [84]

Answer: 2.1925153x10 to the 3rd

Step-by-step explanation: hope it helps

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