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tia_tia [17]
4 years ago
15

Whats the equation of this Circle?

Mathematics
2 answers:
Leviafan [203]4 years ago
7 0

So the answer is this

-2+-7=-5

Kaylis [27]4 years ago
7 0

equation of a circle is given as

(x-a)^2 + (y-b)^2 = r^2

where (a,b) is coordinates of center of the circle and r is radius.

as per shown in graph we can see center of circle.is ( -7, -2)

now let's calculate radius. we have to calculate distance between any point on circle and center . let's take point (-7,0) on the circle shown in graph.

r = √((-7-(-7))^2 + (0-(-2))^2

r = √4 = 2

so equation is

(x -(-7))^2 + (y - (-2))^2 = 2^2

(x +7)^2 + (y +2)^2 = 4

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Answer:

36+12m

Step-by-step explanation:

12 * 3 = 36

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Using the distributive property, the answer would be: 36+12m

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4 years ago
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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
If (x, y) is a solution to the system of equations, what is the value of y? 1/4 x + 1/8 y = 2 1/3 x + 1/2 y = 4 A) 4 B) 6 C) -6
andre [41]
<h3>The value of y is 4</h3>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

\frac{1}{4}x + \frac{1}{8}y =2 ---------- eqn\ 1\\\\\frac{1}{3}x + \frac{1}{2}y = 4 -------------- eqn\ 2

We have to find value of y

From eqn 1,

\frac{1}{4}x + \frac{1}{8}y =2 \\\\2x + y = 2 \times 8\\\\2x + y = 16 ---- eqn\ 3

From eqn 2,

\frac{1}{3}x + \frac{1}{2}y = 4\\\\2x + 3y = 4 \times 6\\\\2x + 3y = 24 ------ eqn\ 4

Subtract eqn 3 from eqn 4

2x + 3y = 24

2x + y = 16

( - ) -----------------

2y = 8

y = 4

Thus value of y is 4

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