4.0987 rounded to the nearest tenth.
4.0987
^ This is the tenths place
Look at the number after it, if it's 5 or more, round up, if it's 4 or less, round down.
<span>It's 9, so we round up to 4.1</span>
<h2>A = 0.625</h2>
There are 8 points between 1 and 0 so divide 1 by 8.
1 / 8 = 0.125
Each point has a value of 0.125.
You can minus 0.125 from 1 until you reach A.
Or you can multiple 0.125 by the number of points from 0 to A, including A.
1 - 0.125 - 0.125 - 0.125 = 0.625
0.125 * 5 = 0.625
<h2>A = 0.625</h2>
We are told that the first term is 2. The next term is 7(2) = 14; the third term is 7(14) = 98. And so on. So, the first term and the common ratio (7) are known.
The nth term of this geometric series is a_n = 2(7)^(n-1).
Check: What is the first term? We expect it is 2. 2(7)^(1-1) = 2(1) = 2. Correct.
What is the third term? We expect it is 98. 2(7)^(3-1) = 2(7)^2 = 98. Right.<span />
9514 1404 393
Answer:
Step-by-step explanation:
The decay factor is 1 -25% = 0.75 per hour, so the exponential equation can be written ...
r(t) = 1450·0.75^t . . . . . milligrams remaining after t hours
__
a) After 4 hours, the amount remaining is ...
r(4) = 1450·0.75^4 ≈ 458.79 . . . mg
About 459 mg will remain after 4 hours.
__
b) To find the time it takes before the amount remaining is less than 5 mg, we need to solve ...
r(t) < 5
1450·0.75^t < 5 . . . . use the function definition
0.75^t < 5/1450 . . . . divide by 1450
t·log(0.75) < log(1/290) . . . . . take logarithms (reduce fraction)
t > log(1/290)/log(0.75) . . . . . divide by the (negative) coefficient of t
t > 19.708
It will take about 20 hours for the amount of the drug remaining to be less than 5 mg.