Answer:
7.55 miles
Step-by-step explanation:
Given that :
Distance of descent = 1.5 miles
New elevation point after descent = 6.05 miles
The initial elevation of the plane before descent will be :
New elevation point after descent + Distance of descent
(6.05 miles + 1.5 miles)
= 7.55 miles
All I can tell you is 12x16=192
Answer:
(4,5)
Step-by-step explanation:
The "feasible region" has vertices (0,0), (7,0), (5,4), and (4,5)
P = 5x + 6y
Plug in each vertices in P and find out which give maximum value
(0,0) => P= 5(0) + 6(0) = 0
(7,0) => P= 5(7) + 6(0) = 35
(5,4) => P= 5(5) + 6(4) = 49
(4,5) => P= 5(4) + 6(5) = 50
We got maximum P=50 for vertex (4,5)
So the coordinates of the point that has the maximum value is (4,5)
I can’t solve this because there is not enough information
There's a formula for that.
KE = (1/2)mv²
... = (1/2)(2000 kg)(30 m/s)²
... = 900,000 kg·m²/s²
... = 900,000 J
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It is helpful to know the relationship between kilograms, meters, seconds, and Newtons or Joules.
1 J = 1 kg·m²/s²