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TEA [102]
2 years ago
9

Help................​

Mathematics
1 answer:
Rina8888 [55]2 years ago
4 0

Answer:  DB is 5

Step-by-step explanation:

Alright, lets get started.

Since given that AD is parallel to CB.

And AB is parallel to CD.

And the angle A is given as 90°

It means the given figure is a rectangle.

And the diagonals of the rectangle are equal to each other.

So, DB=AC

So, DB=5

Hence the answer is 5 ...     Answer

Hope it will help :)

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(
SSSSS [86.1K]

Answer:

We conclude that:

\sqrt{\left(-81\right)x^2}=9ix

Step-by-step explanation:

Given the radical expression

\sqrt{\left(-81\right)x^2}

simplifying the expression

\sqrt{\left(-81\right)x^2}

Remove parentheses:  (-a) = -a

\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}

Apply radical rule:   \sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0

                 =\sqrt{-1}\sqrt{81x^2}

Apply imaginary number rule:  \sqrt{-1}=i

                 =i\sqrt{81x^2}

Apply radical rule:   \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0

                  =\sqrt{81}i\sqrt{x^2}

                  =9i\sqrt{x^2}

Apply radical rule:  \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

                  =9ix

Therefore, we conclude that:

\sqrt{\left(-81\right)x^2}=9ix

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