Answer:
The mean age of the frequency distribution for the ages of the residents of a town is 43 years.
Step-by-step explanation:
We are given with the following frequency distribution below;
Age Frequency (f) X 
0 - 9 30 4.5 135
10 - 19 32 14.5 464
20 - 29 12 24.5 294
30 - 39 20 34.5 690
40 - 49 25 44.5 1112.5
50 - 59 53 54.5 2888.5
60 - 69 49 64.5 3160.5
70 - 79 13 74.5 968.5
80 - 89 <u> 8 </u> 84.5 <u> 676 </u>
Total <u> 242 </u> <u> 10389 </u>
Now, the mean of the frequency distribution is given by the following formula;
Mean =
=
= 42.9 ≈ 43 approx.
Hence, the mean age of the frequency distribution for the ages of the residents of a town is 43 years.
Answer:
Step-by-step explanation:
<u>Prime factors of 2100 are:</u>
<u>The single-digit divisors are:</u>
- 1, 2, 3, 2*2= 4, 5, 2*3= 6, 7
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<u>Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:</u>
- 2100/1 = 2100, yes
- 2100/2 = 1050, yes
- 2100/3 = 700, yes
- 2100/4 = 525, yes
- 2100/5 = 420, yes
- 2100/6 = 350, yes
- 2100/7 = 300, yes
- 2100/8 = 262.5, no
- 2100/9 = 233.33, no
So all the numbers from 1 to 7
Answer:
Step-by-step explanation:
