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Viktor [21]
2 years ago
13

Which type of graph would best show the number of red grapes and the number of green grapes in several cups?

Mathematics
1 answer:
Nataly [62]2 years ago
6 0
Line graph is correct
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Can so.eone explain to me by what bisecting intervals are?​
Tasya [4]

When you bisect something, you cut it into two equally sized pieces. (from Latin: "bi" = two, "sect" = cut)

Bisecting an interval creates two smaller intervals each with half the length of the original interval. Some examples:

• bisecting [0, 2] gives the intervals [0, 1] and [1, 2]

• bisecting [-1, 1] gives the intervals [-1, 0] and [0, 1]

• bisecting an arbitrary interval [a,b] gives the intervals \left[a,\frac{a+b}2\right] and \left[\frac{a+b}2,b\right]

7 0
2 years ago
Can someone please help me with this problem? An explanation would be great, but it can be short. Thank you!!
ss7ja [257]

We are given two points: (4, -8) and (8, 5)

General equation of a line: y = mx + c

First find m (the gradient). There is a formula for this: (change in y)/(change in x) = gradient

(5 - -8) / (8 - 4) = (13) / (4) = 3.25 = m

y = 3.25x + c

Now we need to find c (the y-intercept; the value of y when x=0).

Substitute in any one of the coordinates - let's use (8, 5)

(5) = 3.25(8) + c

(5) = 26 + c

c = -21

The equation of the line: y = 3.25x - 21


I think that this answer is correct - sorry if it seems rushed.

Hope this answer helps :)

7 0
3 years ago
4. Bobbie scores m marks in a test. <br> Georgia scores three times as many marks as Bobbie.
xxTIMURxx [149]

Marks of Bobbie = x

Then, marks of Georgia

= 3 times marks of Bobbie

= 3 times m

= 3 × m

= 3m

6 0
3 years ago
A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 ki
shepuryov [24]

Answer

given,

mean = 12 Kg

standard deviation = 0.5 Kg

assume the observed statistic is = 11.1

 now, \bar{X}=11.1 , \mu = 12 , \sigma = 0.5

assuming the number of sample = 4

n = 4

Hypothesis test:

H₀ : μ≥ 12

Ha : μ < 12

now,

significant level α = 0.05

z* = \dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

z* = \dfrac{11.1-12}{\dfrac{0.5}{\sqrt{4}}}

     z* = -3.60

Test statistics, Z* = -3.60

P-value

P(Z<-3.60) = 0.002 (from z- table)

P- value = 0.002

now,

reject the value of H₀ when P-value < α

    0.002 < 0.05

since, it is less P-value < α , we have to reject the null hypothesis

5 0
3 years ago
David will spend at most $39 on gifts. So far, he has spent $22. What are the possible additional amounts he will spend? Use c f
iren2701 [21]

Answer:

c\leq \$17

Step-by-step explanation:

Let

c -----> the additional amount (in dollars) David will spend

we know that

The word " at most" in this context means "less than or equal to"

The amount David has spent plus possible additional amounts he will spend must be less than or equal to $39

so

The inequality that represent this situation is

22+c\leq 39

solve for c

subtract 22 both sides

c\leq 39-22

c\leq \$17

The maximum amount he could spend is $17

7 0
2 years ago
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