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MatroZZZ [7]
2 years ago
9

At a picnic there were 3 times as many adults as children and twice as many women as men. If there was a total of x men, women,

and children at the picnic, how many men were there, in terms of x ?
A. x/2B. x/3C. x/4D. x/5E. x/6
Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
5 0

Answer:

\dfrac{x}{4}

C is correct.

Step-by-step explanation:

At a picnic,

Number of adults is 3 times as number of children.

Number of women is twice as number of men.

Total number of men, women and children at the picnic be x

Let number of children be c

Let number of men be m

Let number of women be w

# Number of women is twice as number of men, w = 2m

# Number of adults is 3 times as number of children, w + m = 3c

      2m + m = 3c     (∴  w=2m )

                c = m

Total number of men, women and children at the picnic be x

∵       c + m + w = x

     m + m + 2m = x

                    4m = x

Number of men, m=\dfrac{x}{4}

Hence, The total number of men will be  \dfrac{x}{4}

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Consider the following least squares specification between test scores and the student - teacher ratio: TestScore = 557.8 + 36.4
GenaCL600 [577]

Answer:

Test score_i= 557.8 +36.42 Income

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

Test score_f = 557.8  + (36.42* 1.01 Income)= 557.8 +36.7842 Income

And the net increase can be founded like this:

Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642

So then the net increase would be:

C. 0.36 points

Step-by-step explanation:

For this case we have the following linear relationship obtained from least squares between test scores and the student-teacher ratio:

Test score_i= 557.8 +36.42 Income

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

Test score_f = 557.8  + (36.42* 1.01 Income)= 557.8 +36.7842 Income

And the net increase can be founded like this:

Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642

So then the net increase would be:

C. 0.36 points

5 0
3 years ago
I^333 simplified. pls answer
Oduvanchick [21]

Given:

i^{333}\begin{gathered} i^{332}i \\  \\ (i^4)^{83}i \end{gathered}

Solving further:

\begin{gathered} \text{ Where:} \\ i^4=1 \\  \\ (1)^{83}i \\  \\ =1i \\  \\ =i \end{gathered}

ANSWER:

i

7 0
11 months ago
Which expression is equivalent to (x^1/2y^-1/4z)^-2?
tiny-mole [99]

Answer:

y^1/2/xz^2 option 3

Step-by-step explanation:

(x^1/2 y^-1/4 z)^-2= x^(-1/2*2) y^(1/4*2) z^-2= x^-1 y^1/2 z^-2= y^1/2/xz^2

7 0
3 years ago
How to do this does anyone know if u do i will make u brainlist
Studentka2010 [4]

Answer:

Those functions are for a graph.

Step-by-step explanation:

You can compare them by heading to a website like desmos and plugging in each function, I think they even do tables as well.

These are functions that can be graphed, I assume you know what that is, if not, look it up.

good luck

6 0
1 year ago
Read 2 more answers
If (x+2) is a factor of x^3-6x^2+kx+10, k=
Alja [10]
If a binomial (x-a) is a factor of a polynomial, then a is a root of this polynomial.

(x+2)=(x-(-2)) \Rightarrow a=-2\\\\
(-2)^3-6\cdot(-2)^2+k\cdot(-2)+10=0\\
-8-24-2k+10=0\\
-2k=22\\\
\boxed{k=-11}


3 0
2 years ago
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