The overall charge of the given compound of potassium and Arsenic is zero (0).
<h3>What is the charge of an atom?</h3>
An atom consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons. When the number of protons exceed the number of electrons, the atom will positively charged and it will be negatively charged if the number of electrons exceed the number of protons.
For the given compound;
- KAs; As (Arsenic = -3) + K (potassium = +3)
- KAs overall charge = -3 + 3 = 0
Thus, the overall charge of the given compound of potassium and Arsenic is zero (0).
Learn more about charge here: brainly.com/question/25922783
#SPJ1
Answer:
81 L gas
General Formulas and Concepts:
<u>Ideal Gas Law</u>
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 3.6 mols gas at STP
[Solve] volume (L) of gas
<u>Step 2: Convert</u>
- [DA] Set up:
- [DA] Multiply [Cancel out units]:
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
80.64 L gas ≈ 81 L gas
<em>Answer:</em>
- Such a alkane has only one ring that is cyclooctane.
<em>Explanation:</em>
- The general formula of alkane is CnH2n+2. Such general formula is applicable for only open chain alkane.
- When alkane form ring, then this formula does not remain valid.
- The general formula of Cycloalkane is CnH2n.
As in this case, there are 8-carbon and 16-hydrogen that is according to above cycloalkane formula.
Colligative properties are usually used in relation to solutions.
Colligative properties are those properties of solutions, which depend on the concentration of the solutes [molecules, ions, etc.] in the solutions and not on the chemical nature of those chemical species. Examples of colligative properties include: vapour pressure depression, boiling point elevation, osmotic pressure, freezing point depression, etc.
For the question given above, the correct option is D. This is because the statement is talking about freezing point elevation, which is not part of colligative properties.
Answer:
Molarity=Moles of solute/volume of solution in Litres
Simply imputing your values
you have
0.75/65
0.0115M.