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Inessa05 [86]
2 years ago
9

Write a balanced half-reaction for the oxidation of manganese ion (mn2 ) to solid manganese dioxide (mno2) in acidic aqueous sol

ution. Be sure to add physical state symbols where appropriate.
Chemistry
1 answer:
Helen [10]2 years ago
5 0

Answer:

Mn2+(aq) + 2H2O(l)  ⇒ MnO2(s) + 4H+(aq) + 2e-

Explanation:

Step 1: Data given

The oxidation number of manganese ion (Mn2+ ) is +2

The oxidation number of manganese dioxide  is +(MnO2)4

This means the oxidation number from Mn will go from +2 to +4, since it's increased, this is an oxidation reaction

Mn2+(aq)  ⇒ MnO2(s)

We have to balance both sides. Mn is already the same. But on the right side we have O atoms. T obalance both sides we have to add O atoms to the left side. This by adding 2x H2O

Mn2+(aq) + 2H2O(l)  ⇒ MnO2(s)

Now the amount of O atoms is balanced, but we have H- atoms at the left side. To balance we have to add 4 H atoms to the right side

Mn2+(aq) + 2H2O(l)  ⇒ MnO2(s) + 4H+(aq)

Now the amount of atoms is balanced at both sides. We also have to check if the charge on both sides is the same.

Since the left side has a charge of +2, and right has a charge of +4, we have to add 2 electrons to balance this.

Mn2+(aq) + 2H2O(l)  ⇒ MnO2(s) + 4H+(aq) + 2e-

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Answer:

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Explanation:

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3 0
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Answer:

The answer to your question is below

Explanation:

Data

Aqueous acetic acid

Aqueous barium hydroxide

Formula

Acetic acid    CH₃CH₂COOH

Barium hydroxide   Ba(OH)₂

Neutralization reaction

        CH₃CH₂COOH    +    Ba(OH)₂      ⇒  Ba( CH₃CH₂COO)₂ + H₂O

                                                                    Barium acetate + H₂O

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6 0
2 years ago
What’s the physical properties in calcium chloride
vodka [1.7K]

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3 0
2 years ago
How many milliliters of 5.0M K2Cr2O7 solution must be diluted to prepare 250.0 mL of 0.37 M solution
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3 0
3 years ago
compute the mass-specific enthalpy change associated with Nz that is undergoing a change in state from 400 k to 800 k
Kitty [74]

Answer:

The correct answer is "430 kJ/kg". A further explanation is given below.

Explanation:

The given values are:

T₁ = 400 k

T₂ = 800 k

The average temperature will be:

= \frac{T_1+T_2}{2}

= \frac{400+800}{2}

= 600 \ k

From table,

At 600 k the C p will be = 1.075

Now,

⇒ The specific enthalpy = Cp(T_2-T_1)

⇒                                \Delta h=1.075 (800-700)

⇒                                      =430 \ kJ/kg

8 0
2 years ago
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