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Amanda [17]
4 years ago
15

Plz help it’s the ANDREA ONe

Mathematics
1 answer:
Marianna [84]4 years ago
7 0
Assuming that all measurements are the same, as the formula for volume of a box is simply

S^3. Make this expression equal 90 cubic inches. Then take the cube root to solve for s. The value of s are your measurements for the length width and height of the box.

S = 4.48 in.







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What is the value of m in the equation 1/2m - 3/4 = 16 when n=8
kow [346]

Answer:

answer is 33.5

Step-by-step explanation:

1/2m-3/4=16

1/2m=16+3/4

1/2m=64+3/4

1/2m=67/4

m=67/4×2

m=33.5

8 0
3 years ago
A 50% increase followed by a 33.33 percent decrease. Greater or larger that original amount?
wariber [46]
Well the answer for that question would be a greater number
5 0
3 years ago
Read 2 more answers
What is .16 as a fraction
tatiyna

Answer:

16/100

Step-by-step explanation:

the decimal is 16 hundreths of one

4 0
3 years ago
Read 2 more answers
Find the area of the shape shown below
myrzilka [38]

Answer: 42.5

Step-by-step explanation:

9 x 3.5 = 31.5

2 x 2 = 4

2 x 2 / 2 = 2

2 x 5 / 2 = 5

31.5 + 4 + 2 + 5 = 42.5

6 0
3 years ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Marina86 [1]

Answer:

Divergent.

Step-by-step explanation:

We have been given an integral \int\limits^\infty _1 {\frac{1}{x^{0.999}} \, dx. We are asked to determine whether the given integral diverges or converges.

\int _1^{\infty }\:\:\:\frac{1}{x^{0.999}}\:\:\:dx

\int _1^{\infty }\:\:\:\frac{1}{x^{0.999}}\:\:\:dx=\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=\frac{x^{-0.999+1}}{-0.999+1}

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=\frac{x^{0.001}}{0.001}

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=1000x^{0.001}

Let us compute the boundaries.

1000(\infty)^{0.001}=\infty

1000(1)^{0.001}=1000

Since \infty-1000 is not a finite number, therefore, the given integral diverges.

4 0
3 years ago
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