Plz help it’s the ANDREA ONe

Mathematics

1 answer:

Marianna [84]3 years ago

7 0

Assuming that all measurements are the same, as the formula for volume of a box is simply

S^3. Make this expression equal 90 cubic inches. Then take the cube root to solve for s. The value of s are your measurements for the length width and height of the box.

S = 4.48 in.

You might be interested in

Fed has a break at 5:41 but it only 31 min what time does he go back

sp2606 [1]

Answer:

6:11

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Hey, would anyone know the answers/correct matchup to this? (USA test prep)

Komok [63]

Answer:

there you go

Step-by-step explanation:

8 0

3 years ago

Given the following winning percentages of the teams in a league (for a single year) compute the within-season standard deviatio

Masja [62]

Answer:

(b) 0.251

Step-by-step explanation:

1. Standard deviation equation:

$SD=\sqrt{\frac{\sum\limits^N_i {(x_{i}-X)^{2} } }{N} }$

Where X is the mean of the data, and N the amount of data. Then, N=5

2. Estimate the Mean:

$X=\frac{0.750+0.750+0.200+0.600+0.200}{5}=\frac{2.5}{5}=0.5\\$

3. Caclulate Standard deviation:

$SD=\sqrt{\frac{{(0.750-0.500)^{2}+(0.750-0.500)^{2}+(0.200-0.500)^{2}+(0.600-0.500)^{2}+(0.200-0.500)^{2} } }{5} }$

$SD=\sqrt{\frac{0.315}{5} }=\sqrt{0.063}\\SD=0.251$

7 0

3 years ago

Please help will give brainliest

deff fn [24]

Since the sum of the probabilities of all possible outcomes must be 100%, we can deduce the following:

Cooking in under 20 minutes: 10%
Cooking between 20 and 30 minutes: 85%
Cooking in more than 30 minutes: 5%

In fact, the probabilities of cooking in less than 20 or more than 30 sum up to 15%, which means that the remaining outcome (i.e. cooking time between 20 and 30) must complete this probability to 15, and in fact 15+85=100.

That being said, all three answers are simply a combination of these three scenarios: let C be the cooking time, for aesthetic reasons:

$P(C\geq 20) = P(20 \leq C \leq 30)+P(C\geq30) = 85\%+5\%=90\%$