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aleksandr82 [10.1K]
3 years ago
13

Please help. Algebra.

Mathematics
2 answers:
max2010maxim [7]3 years ago
7 0
The pic is laggy can you post it again
diamong [38]3 years ago
4 0

Answer:

3. -3

4. 4

Step-by-step explanation:

3 . so  h^{2} = g^{?+3} h^{2}, we cancel the h^{2} out and it leaves us with 1=g^{?+3}

Which means ?+3=0, and ?=-3

4. so k^{?}  = k^{4}, ?=4

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The perimeter of a rectangle is 800 yards. What are the dimensions of the rectangle if the length is 60 yards more than the widt
mote1985 [20]
The length would be 230, and the width would be 170, and since there are 4 sides there would be 2 of each. So 230x2=460 and 170x2=340. 460+340= 800
3 0
4 years ago
X = 3y - 6 2x - 4y = 8 Solve the system of equations using substitution.
Brut [27]
Hello

x = 3y - 6
2x - 4y = 8
We need to start by solving 3y - 6 for x
Substitute 3y -6 for x in 2x
2x - 4y = 8
2(3y - 6) - 4y = 8
2y - 12 = 8
2y = 8 + 12
2y = 20
Divide both sides by 2
2y/2 = 20/2
y = 10

Now, substitute 10 for y in x= 3y
x = 3y - 6
x = 3(10) - 6
x = 30 - 6
x= 24

Answer : x = 24 and y=10

I hope this help!
7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
Four times as many apples. Algebraic expression
Leno4ka [110]
4x. hope that helped
8 0
4 years ago
What is the GFC of 40 and 60
Svetradugi [14.3K]

Answer:

GCF: 20

Step-by-step explanation:

The thing you want to do is factor both numbers down to their lowest primes.

40:2 * 2 * 2 * 5

60:2 * 2 * 5 * 3

Now underline what is in both sets of primes. I'll bold them. The number that is bolded comes from 2 * 2 * 5 which is 20

The highest common factor is 20

3 0
3 years ago
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