Answer:
119.38
Step-by-step explanation:
the circumference is πd so it is 19 X 2, which is 38, times π, which is 38π. this equals 119.38
<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.
Hello!
f(g(x)) = 4 - <u>2</u><u> </u><u>×</u><u> </u><u>(</u><u>3</u><u>x</u><u>²</u><u>)</u> <=>
<=> f(g(x)) = 4 - 6x²
Answer: B. f(g(x)) = 4 - 6x²
Good luck! :)
Answer:
if its 4 as a whole number 4/1
Step-by-step explanation: