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3 years ago

Grade 7 : Help, anyone? Urgent!!!!!!!!

Mathematics

1 answer:

MariettaO [177]3 years ago

4 0

Materials = $4.25
Labor = $5.35
Sale Price = $16.99

A.) Profit = Sale Price - (Materials + Labor)
Profit = 16.99 - (4.25 + 5.35)
Profit = 16.99 - (9.60)
Profit = $7.39

Profit / Sale Price = % Profit
7.39 / 16.99
or
739 / 1699

B.) % Profit = Profit / Sale Price × 100
  % Profit = 7.39 / 16.99 × 100
  % Profit = 0.43496 × 100
  % Profit = 43.496 %
  % Profit = 43 %

C.) Total Sales = $324.86

Necklaces Sold = Total Sales / Individual Sale Price
Necklaces Sold = 324.86 / 16.99
Necklaces Sold = 19.12

**This question is absolutely ridiculous because either she made money from tips or someone either paid too much or too little**

Total Profit = Necklaces Sold × [Sale Price - (Materials + Labor)]
Total Profit = 19 × [16.99 - (4.25 + 5.35)]
Total Profit = 19 × (7.39)
Total Profit = $140.41

OR

Total Profit = 20 × (7.39)
Total Profit = $147.80

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If a soccer ball hits a net with a force of 12 N, the net exerts a force of ____ back on the soccer ball. 0 N 6 N 12 N 24 N

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Answer:

12 N

Explanation:

The concept of this question is based on Newton's third law

This law states that:

"For every action there is a reaction that is equal in magnitude but opposite in direction"

The equation representing this law is:

F₁₂ = -F₂₁

Now, for the given problem:

We have that the ball exerted a force of 12 N on the net

Applying the above law, the net would exert a force of equal magnitude and opposite direction to that of the ball

Therefore, the net will exert a force of 12 N on the ball

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A group of hikers is descending a mountain at a rate of 400 feet per hour. What is the change in the elevation of hikers after 6

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If I have a shirt that is $32 and 25% off what’s the new price

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It took a car 5 days to travel 1459 miles. What was the car's average speed, in miles per hour?

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4 years ago

A steel safe with mass 2200 kg falls onto concrete. Just

Virty [35]

The kinetic energy of the safe increases the force exerted by the concrete

to several times the weight of the safe.

The magnitude of the force exerted on the safe by the concrete on the is approximately $\underline{29.\overline 3 \, \mathrm{MN}}$

The concrete exerts a force that is approximately 1,359.16 times the weight of the safe.

Reasons:

First part

The mass of the steel safe, m = 2,200 kg

Velocity of the safe just before it hits the concrete, v = 40 m/s

The amount by which the safe was compressed, d = 0.06 m

The kinetic energy, K.E., of the safe just before it hits the round is therefore;

$\displaystyle K.E. = \mathbf{\frac{1}{2} \cdot m \cdot v^2}$

$\displaystyle K.E._{safe} = \frac{1}{2} \times 2,200 \times 40^2 = 1,760,000 \ Joules$

Work done by concrete, W = Force, F × Distance, d

$\displaystyle Force, \, F = \mathbf{\frac{Work, \, W}{Distance, \, d}}$

By the law of conservation of energy, we have;

The work done by the concrete, W = The kinetic energy, K.E. given by the safe

W = K.E. = 1,760,000 J

The effect of the work = The change in the height of the safe

Therefore;

The distance, d, over which the force of the concrete is exerted = The change in the height of the safe = 0.06 m

d = 0.06 m

Therefore;

$\displaystyle The \ force \ of \ the \ concrete, \, F = \frac{1,760,000\, J}{0.06 \, m} = 29,333,333. \overline 3 \, N = 29.\overline 3 \ MN$

The force of the concrete on the safe = $\underline{29.\overline 3 \ MN}$

Second part:

The gravitational force of the Earth on the safe, W = The weight of the safe

W = Mass, m × Acceleration due to gravity, g

W = 2,200 kg × 9.81 m/s² ≈ 21,582 N

The ratio of the force exerted by the concrete to the weight of the safe is found as follows;

$\displaystyle Ratio \ of \ forces = \frac{29.\overline 3 \times 10^6 \, N}{21,582 \, N} = \frac{4,000,000}{2,943} \approx \mathbf{1359.16}$

The force exerted by the concrete is approximately 1,359.16 times the weight of the safe.

Learn more here:

brainly.com/question/21060171

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3 years ago