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Lana71 [14]
4 years ago
12

What element(s) is/are necessary for a geometric proof?

Mathematics
2 answers:
stellarik [79]4 years ago
8 0
A theorem to prove, a series of logical statements, and reasons for the statements.
Nonamiya [84]4 years ago
7 0
<span>a series of logical statement</span>
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Need help due asap. n.
sergey [27]

Answer:

y = -3x + 1

Step-by-step explanation:

y = -3x + 1

y = -3 . -2 + 1

= 6 + 1

y = 7

y = -3x + 1

y = -3 . 2 + 1

= -6 + 1

= -5

y = -3x + 1

= -3 . 4 + 1

= -12 + 1

= -11

so, it should be y = -3x + 1

<h3>#CMIIW</h3>

6 0
3 years ago
Gretchen is using an overhead projector to enlarge a drawing so she can make a poster. The original drawing measures 60 mm wide
podryga [215]
So 60 by 80,
60 <80 so 60=width
she moves it so that width=300
findn height

60:300=80:x
60/300=80/x
muliplyb oth sides by x
60x/300=80
x/5=80
mulitpliy both sides by 5
x=400

the height=400 mm
8 0
4 years ago
What is Pythagorean Theorem?
Lady_Fox [76]

Answer:

Pythagorean theorem, the well-known geometric theorem that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle)—or, in familiar algebraic notation, a2 + b2 = c2.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Aunt Thelma planted an herb garden. She planted rosemary in 2/9 of the garden. She
Reptile [31]

Answer:

\dfrac{17}{45}

Step-by-step explanation:

Fraction on which Rosemary was planted =\dfrac{2}{9}

Fraction on which dill was planted =\dfrac{2}{5}

Let the fraction on which chives was planted=x

Then:

\dfrac{2}{9}+\dfrac{2}{5}+x=1\\$Since the LCM of 9 and 5 is 45\\We multiply all through by 45\\45\left(\dfrac{2}{9}\left)+45\left(\dfrac{2}{5}\right)+45x=45(1)$\\10+18+45x=45\\45x=45-28\\45x=17\\Divide both sides by 45\\x=\dfrac{17}{45}

The fraction of the garden on which Chives was planted is \dfrac{17}{45}

6 0
3 years ago
The second derivative form of xe3x
Galina-37 [17]

Answer:

If you meant the equation was xe^3x



then the first derivative would be 3xe^3x+e^3x using the product rule



Then to find the second derivative you'll have to use both the product rule and sum rule inorder to get the answer.

The 2nd derivative would therefore be 9xe^3x+6e^3x or in factored form

3e^3x(3x+2)

7 0
2 years ago
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