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olasank [31]
3 years ago
15

Simplify the expression below.

Mathematics
2 answers:
mario62 [17]3 years ago
5 0

3 · -8 + 5 - 4 ÷ 2

Use PEMDAS

P=parenthesis

E=exponents

M= multiplication

A= addition

S=subtraction

-24+5- 4÷ 2

-19-2

=-21

Answer is B-21

Margaret [11]3 years ago
4 0

Answer:

B. -21

Step-by-step explanation:

You have to follow PEMDAS

3*-8=-24

So, -24+5-4÷2

-4÷2=-2

So, -24+5-2

Then add and subtract from left to right

-24+5=-19

-19-2=-21

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4^4 + 1/2 step by step
expeople1 [14]
4^4 + 1/2
= (4×4×4×4) + 1/2
= 256 + 1/2
= 256 + 0.5
= 256.5
8 0
3 years ago
An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft 3 . Find the d
denpristay [2]

Answer:

The dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

Step-by-step explanation:

Given : An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft³.

To find : The dimensions of the box that minimize the materials used ?

Solution :

An open top box is to be built with a rectangular base whose length is twice its width.

Here, width = w

Length = 2w

Height = h

The volume of the box V=36 ft³

i.e. w\times 2w\times h=36

h=\frac{18}{w^2}

The equation form when top is open,

f(w)=2w^2+2wh+2(2w)h

Substitute the value of h,

f(w)=2w^2+2w(\frac{18}{w^2})+2(2w)(\frac{18}{w^2})

f(w)=2w^2+\frac{36}{w}+\frac{72}{w}

f(w)=2w^2+\frac{108}{w}

Derivate w.r.t 'w',

f'(w)=4w-\frac{108}{w^2}

For critical point put it to zero,

4w-\frac{108}{w^2}=0

4w=\frac{108}{w^2}

w^3=27

w^3=3^3

w=3

Derivate the function again w.r.t 'w',

f''(w)=4+\frac{216}{w^3}

For w=3, f''(3)=4+\frac{216}{3^3}=12 >0

So, it is minimum at w=3.

Now, the dimensions of the box is

Width = 3 ft.

Length = 2(3)= 6 ft

Height = \frac{18}{3^2}=2\ ft

Therefore, the dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

4 0
3 years ago
How to solve n-5*2/3=3/4
Scorpion4ik [409]

n-5\cdot\dfrac{2}{3}=\dfrac{3}{4}\\\\n-\dfrac{10}{3}=\dfrac{3}{4}\ \ \ \ |\cdot12\\\\12n-12\cdot\dfrac{10}{3}=12\cdot\dfrac{3}{4}\\\\12n-4\cdot10=3\cdot3\\\\12n-40=9\ \ \ \ |+40\\\\12n=49\ \ \ \ \ |:12\\\\n=\dfrac{49}{12}

5 0
3 years ago
I need the answer to this.​
Kamila [148]

Answer:

VERY HARD QUESTIONS SO I WILL TELL YOU LATER

4 0
2 years ago
COLLEGE PREP In the diagram, mLAGC = 38°, m/CGD=71°, and m/FGC = 147 °. Which of the following
Cerrena [4.2K]

The statements that are true are:

A. m<AGB = 19°

D. <BGD is a right angle

<h3>What is a Right Angle?</h3>

A right angle is an angle that measures 90 degrees.

Given the diagram, where:

m<AGC = 38°,

m<CGD = 71°,

m<FGC = 147°

We have the following measures:

1/2(m<AGC) = m<AGB

1/2(38) = 19°

m<CGD + m<AGC = m<BGD

Substitute

71 + 19 = m<BGD

90 = m<BGD

m<BGD = 90° [this is a right angle].

Therefore, the statements that are true are:

A. m<AGB = 19°

D. <BGD is a right angle

Learn more about right angle on:

brainly.com/question/64787

#SPJ1

5 0
1 year ago
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