A = V1 - V0/t.....multiply both sides by t
At = V1 - V0....add V0 to both sides
At + V0 = V1
This is deceptively simple: there are only three terms, one is a constant (1) and two are coefficients of q (4q, -2q). To simplify the like terms, just simplify the terms containing q.
Answer:
Yes, the function is a kernel
Step-by-step explanation:
Given
Document x an z
Function definition! k(x:z)
We want to show that the above is a kernel.
To do this, we'll explicitly construct feature vectors φ(x) and φ(z)
This gives;
K(x,z) =φ(x)·φ(z).
Given than any document; say x and z
A vocabulary V can be constructed.
Vocabulary V must have a finite size of words in the document set..
The feature mapping is constructed as φ(x) for x by the following:
For the kth word wk in V, if wk appears in document x, assign φ(x) k(the kth element ofφ(x)) to be 1; else φ(x)k to 0.
Then the number of unique words common in x and z is φ(x)·φ(z), giving us the kernel
.
0.7(5x+15)=2.9 -(x+3)
3.5x+10.5=2.9-x-3
3.5x+10.5= -0.1- x
4.5x= -10.6
x= -2.3555...
Check:
0.7(5(-2.3555...) +15) = 2.9 -(x+3)
2.2555... = 2.2555...
Answer:
W=5
Step-by-step explanation:
40+4w=12w
-4w -4w
40= 8w
÷8 ÷8
5=w