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uysha [10]
2 years ago
12

Look at photo and answer.

Mathematics
1 answer:
11111nata11111 [884]2 years ago
3 0

Answer:

h.

\frac{9 {x}^{10}(y. {x}^{3}) {}^{2}   }{y.x(3 {x}^{3}) {}^{3}  }  \\  \\  =  \frac{9 {x}^{10}(y {}^{2} )( {x}^{6} ) }{3y. {x}^{10} }  \\  \\  =  \frac{ {3}^{2}  {x}^{16} {y}^{2}  }{3y {x}^{10} }  \\  \\  =  3y {x}^{6}

j.

\frac{(3x. {y}^{7} ) {}^{2}. {x}^{5}  }{3 {x}^{7}  {y}^{4} }  \\  \\  =  \frac{3 {x}^{2} . {y}^{14} . {x}^{5} }{3 {x}^{7} {y}^{4}  }  \\  \\  =  \frac{ {3x}^{7}  {y}^{14} }{3 {x}^{7} {y}^{4}  }  \\  \\  =   {y}^{10}

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