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3 years ago

How to find 60% Of 3/4

2 answers:

3 0

To find 1% of a number, divide by ______. To find 20%, 30%, 40%, 60%, 70%, 80%, or 90% of a number, First find _________% of number and. then multiply by 2, 3, 4, 6, 7, 8, or 9.

NARA [144]3 years ago

3 0

After you divide 3 by 4 and get 75, you multiply that by 60% and you get 0.45.

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The doubling period of a bacterial population is 15 minutes. At time t= 80 minutes, the bacterial population was 90000

Papessa [141]

Answer:

here i finished!

hope it helps yw!

Step-by-step explanation:

The doubling period of a bacterial population is 15 minutes.

At time t = 90 minutes, the bacterial population was 50000.

Round your answers to at least 1 decimal place.

We can use the formula:

A = Ao*2^(t/d); where:

A = amt after t time

Ao = initial amt (t=0)

t = time period in question

d = doubling time of substance

In our problem

d = 15 min

t = 90 min

A = 50000

What was the initial population at time t = 0

Ao * 2^(90/15) = 50000

Ao * 2^6 = 50000

We know 2^6 = 64

64(Ao) = 50000

Ao = 50000/64

Ao = 781.25 is the initial population

Find the size of the bacterial population after 4 hours

Change 4 hr to 240 min

A = 781.25 * 2^(240/15

A = 781.25 * 2^16

A= 781.25 * 65536

A = 51,199,218.75 after 4 hrs

6 0

3 years ago

PLEASE HELPPPPPP ASAPPP I WILL GIVE BRAINLEST FOR THE CORRECT ANSWER

guajiro [1.7K]

Answer:

a. Find the multiples of 4 and 12 in the 30 to 40 range:

4 ⇒ 32, 36, 40

12 ⇒ 36

Answer = 36

b. Divisors of 24 ⇒ 2, 3, 4, 6, 8, 12, 24

Answer = 3

3 is the only odd divisor.

c. Gcd = Greatest common divisor that isn't zero.

35 divisors ⇒ 1, 5, 7, 35

42 divisors ⇒ 1, 2, 3, 6, 7, 14, 21, 42

Answer = 7

d. 98 divisors ⇒ 1,2,7,14,49,98

99 divisors ⇒ 1,3,9,11,33,99

Answer = 1

e. Answer = 25.

A number's greatest divisor is its own self.

6 0

2 years ago

PPLEASE HELP!!!!! WHAT IS THE INITIAL VALUE MEAN FOR THIS GRAPH/FUNCTION

Rudiy27

Amount saved:50I60I70l80l AND ON......
......weeks......:0..I1...l2..l3..l ..........AND ON
amount saved =x
weeks=y
after every y+10=x

6 0

3 years ago

One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

See attachment for possibility tree

Solving (b): The total number of outcome

For urn 1

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

For urn 2

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

5 0

2 years ago

Sally makes 7 out of every 10 shots she takes during practice. If this pattern were to continue, how many would she make during

Levart [38]

Answer:

Step-by-step explanation:

7 for first 10 shots
7 for another 10 shots
7 for last 10 shots

4 0

3 years ago

Read 2 more answers