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Yakvenalex [24]
3 years ago
14

Factor the GCF: 21x3y4 + 15x2y2 − 12xy3.

Mathematics
2 answers:
blondinia [14]3 years ago
7 0

Answer:

Option D.3xy^{2}(7x^{2}y^{2}+5x-4y)

Step-by-step explanation:

We have to factorize the expression given in the question.

21x^{3}y^{4}+15x^{2}y^{2}-12xy^{3}

21x^{3}y^{4}+15x^{2}y^{2}-12xy^{3}=3(7x^{3}y^{4}+5x^{2}y^{2}-4xy^{3})=3x(7x^{2}y^{4}+5xy^{2}-4y^{3})=3xy^{2}(7x^{2}y^{2}+5x-4y)

Option D. 3xy^{2}(7x^{2}y^{2}+5x-4y) is the answer.

-Dominant- [34]3 years ago
6 0
Ugh, these questions.

21x^3y^4 + 15x^2y^2 - 12xy^3

3xy^2 (7x^2y^2 + 5x - 4y)

Clearing up clutter...

3xy² (7x²y² + 5x - 4y)

That's your answer.  Thanks for working my brain. ;)
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