F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
1) D. (2, -6)
2) B. (3, 1)
Step-by-step explanation:
idk how to explain just trust me
if u need any other questions answered message me brother
Answer:
-3.512m
Step-by-step explanation:
−3.512m
=−3.512*m
=−3.512m
He did this then that plus to this and that =334.2
